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SpyIntel [72]
3 years ago
14

Solve the following by substitution : -x + y = 10x - y = 5

Mathematics
2 answers:
koban [17]3 years ago
7 0
\begin{cases} x + y = 10 \\ x - y = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - y = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - (10-x) = 5 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x - 10+x = 5 \end{cases}\\ \\

\begin{cases} y = 10 -x\\ 2x - 10 = 5 \end{cases}\\ \\\begin{cases} y = 10 -x\\ 2x = 5 +10 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ 2x =15 \ \ /:2 \end{cases}\\ \\ \begin{cases} y = 10 -x\\ x =\frac{15}{2} \end{cases}\\ \\

\begin{cases} y = 10 - 7\frac{1}{2}\\ x =7\frac{1}{2} \end{cases}\\ \\ \begin{cases} y = 2\frac{1}{2}\\ x = 8\frac{1}{2} \end{cases}\\ \\
 

Virty [35]3 years ago
5 0
Your question is  -

x + y = 10
x - y = 5

Now, let us solve this system by the substitution method.

According to equation 2 ,

x - y = 5

thus, x = 5 + y

Substituting the value of x in equation 1,

(5 + y) + y = 10

5 + 2y = 10

2y = 10 - 5 = 5

thus, y = 5/2


Substituting the value of y in value of x,

x = 5 + y

= 5 + 5/2

= 15/2

Thus, x = 15/2 ( or 7.5) y = 5/2 ( or 2.5)
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Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of converge
tresset_1 [31]

Answer:

Radius of the convergence is R = \frac{1}{21}

and,

The Interval of convergence is -\frac{1}{21}

Step-by-step explanation:

Given function : Σ(21x)^k

Now,

Using the ratio test, we have

R = \lim_{n \to \infty} |\frac{21x^{k+1}}{21x^{k}}|

or

R = \lim_{n \to \infty} |\frac{21x^{k}\times21x^{1}}{21x^{k}}|

or

R = \lim_{n \to \infty} |21x^{1}|

now,

for convergence R|x| < 1

Therefore,

\lim_{n \to \infty} |21x^{1}| < 1

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-\frac{1}{21}

and,

Radius of the convergence is R = \frac{1}{21}

and,

The Interval of convergence is -\frac{1}{21}

8 0
3 years ago
Two integers, a and b, have a product of 36. What is the least possible sum of a and b?
Minchanka [31]
<h3>Answer:  12</h3>

==============================================================

Explanation:

The two integers multiply to 36, so,

ab = 36

which solves to

a = 36/b

Then we want to add the numbers such that we get the smallest possible result.

a+b = (36/b)+b

So we want (36/b)+b to be as small as possible.

Let's say we replace b with x and we consider this function

f(x) = (36/x) + x

The goal is to find when f(x) is smallest, ie, we want to minimize the function.

If we were to graph out the function, we get the curve shown below.

To make things easier, we'll only focus on positive values of x.

The lowest part of the curve is what we're after. Using the "minimum" function/feature on the graphing calculator, we would then find the lowest point occurs at (6,12). This point is considered a local minimum because it's the lowest point in that given neighborhood of x values.

So the input x = 6 leads to the smallest output f(x) = 12.

This in turn means b = 6 is going to pair with a = 36/b = 36/6 = 6.

In short, a = 6 and b = 6.

----------------------

As a check,

a*b = 6*6 = 36

a+b = 6+6 = 12

We can make a table of various values to help confirm that 12 is the smallest sum.

Side note: If you're not allowed to use a graphing calculator, then you'll need to use calculus.

8 0
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Answer:

A

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1/2x-4=-2x-9...u vil get the ans

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two ratios are equal and form a proportion.

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