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In parallelogram HIJK, the measure of angle H is 45 degrees. 1.Find the measure of J and explain how you know

s2008m [1.1K]

Answer:

45°

Step-by-step explanation:

A parallelogram is a polygon with 4 sides and 4 angles (that is a quadrilateral).

For a parallelogram ABCD, Opposite sides and opposite angles are equal (i.e. BC = AD and ∠A = ∠C).

Consecutive angles are supplementary that is ∠A + ∠B = 180°.

The diagonals of a parallelogram bisect each other also separating the parallelogram into two congruent triangles.

In parallelogram HIJK, ∠H and ∠J are opposite angles. hence:

∠H = ∠J (opposite angles of a parallelogram are equal)

∠J = 45°

8 0

2 years ago

a video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to

7nadin3 [17]

slope is $0.10 ($1.00 per 10 tokens = $0.10)

y-intercept is $60 ($60 is the annual fee)

y = .10x + 60 (y = mx + b)

domain is x ≥ 0 (you can't buy a negative number of token)

range is y ≥ 60 (input the domain (x ≥ 0) to find the range)

Answer: the y-intercept of the function is $60

6 0

2 years ago

Read 2 more answers

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

Consider the set of differences, denoted with d, between two dependent sets: 84, 85, 83, 63, 61, 100, 98. Find the sample standa

sveta [45]

Answer:

The sample standard deviation is 15.3.

Step-by-step explanation:

Given data items,

84, 85, 83, 63, 61, 100, 98,

Number of data items, N = 7,

Let x represents the data item,

Mean of the data points,

$\bar{x}=\frac{84+85+83+63+61+100+98}{7}$

$=82$

Hence, sample standard deviation would be,

$\sigma= \sqrt{\frac{1}{N-1}\sum_{i=1}^{N} (x_i-\bar{x})^2}$

$=\sqrt{\frac{1}{6}\sum_{i=1}^{7} (x_i-82)^2}$

$=\sqrt{\frac{1}{6}\times 1396}$

$=\sqrt{232.666666667}$

$=15.2534149182$

$\approx 15.3$

4 0

2 years ago

vicky has already taken 25 pages of notes on her own and she will take 5 pages during each hour of class. in all how many hours

Lilit [14]

The answer 24..................

5 0

3 years ago