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nordsb [41]
3 years ago
7

Which trophic level of a marine food chain breaks down organisms from all of the other levels?

Biology
1 answer:
Sonja [21]3 years ago
5 0
Decomposers break down the dead decaying body parts of all other organisms. They are also known as saprophytes. Apart from this, the top consumers like sharks, dolphin etc. eat away the smaller trophic organisms like squids, fishes etc,. But after the death of the tertiary consumers, they are also decomposed by the decomposers.
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What is the highest level of protein structure in human insulin, which has two polypeptides of different mass linked by several
-Dominant- [34]

The highest level of protein structure in human insulin, which has two polypeptides of different mass linked by several disulfide bonds Quaternary structures.

  • The fundamental structure of a protein is only the arrangement of the amino acids in a polypeptide chain.
  • In a medical environment, a doctor or nurse may also administer intravenous (into a vein) injections of human insulin solution. You will be closely observed by a doctor or nurse for side effects. Although it can reduce blood sugar levels, human insulin can not treat diabetes.
  • Disulfide bonds are important because they control the stability and conformational dynamics of proteins.
  • The case of proteins, which are frequently disulfide linked and must survive stresses resulting from their typical biological function, is particularly significant.

To learn more about insulin.

brainly.com/question/1398952

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4 0
1 year ago
The prime factorization of blank is 24 × 5.
NeX [460]

Answer:

80

Explanation:

7 0
2 years ago
Read 2 more answers
What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent as
ASHA 777 [7]

Answer:

(a) AABBCC × aabbcc->AaBbCc     → 1

(b) AABbCc × AaBbCc->AAbbCC   → 1/32

(c) AaBbCc × AaBbCc->AaBbCc     → 1/8

(d) aaBbCC × AABbcc->AaBbCc    → 1/2

Explanation:

In such cases we calculate the probability of each allelic pair separately.

(a) AABBCC × aabbcc -> AaBbCc  

Aa  Aa   Aa  Aa           Bb  Bb  Bb  Bb         Cc  Cc  Cc  Cc

↓                                   ↓                                ↓  

4/4 = 1                          4/4 = 1                       4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 4 will be Bb so the probability is 4/4 = 1.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc   = 1 x 1 x 1 = 1.                

(b) AABbCc × AaBbCc -> AA bb CC

AA  AA   Aa  Aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

↓                                                        ↓           ↓  

2/4                                                    1/4          1/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be AA so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 1 will be bb so the probability is 1/4.

In case of gene C, out of the 4 probable allelic combinations, 1 will be CC so the probability is 1/4.

So, the total probability of getting AA bb CC = 2/4 x 1/4 x 1/4 = 1/32.

(c) AaBbCc × AaBbCc -> AaBbCc

AA  Aa   Aa  aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

        ↓                                  ↓                               ↓  

       2/4                               2/4                           2/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be Aa so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 2 will be Cc so the probability is 2/4.

So, the total probability of getting AaBbCc = 2/4 x 2/4 x 2/4 = 1/8.

(d) aaBbCC × AABbcc->AaBbCc

Aa  Aa   Aa  Aa               BB  Bb  Bb  bb          Cc  Cc  Cc  Cc

      ↓                                        ↓                                ↓  

4/4 = 1                                       2/4                          4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc = 1 x 2/4 x 1 = 1/2.

5 0
3 years ago
What is the correct order from highest level to lowest level of taxonomic hierarchy?
horrorfan [7]

Answer:

The current taxonomic system now has eight levels in its hierarchy, from lowest to highest, they are: species, genus, family, order, class, phylum, kingdom, domain.

Explanation:

7 0
2 years ago
Refer to the illustration above. The structure labeled D is a(n)
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Theres not a photo there, or like i cant see one x
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2 years ago
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