All cells come from living things. True or false?

SIZIF [17.4K]

Answer:

The process occurring in Box A is Glycolysis

Explanation:

Glycolysis is the pathway by which glucose, a six-carbon molecule is oxidized to molecules of pyruvate, a three-carbon molecule with the release of ATP and electrons which are carried by NADH molecules.

The process occurs in the cytoplasm of cells and requires 10 glycolytic enzymes.

The pyruvate molecules from glycolysis is first oxidized to acetyl-CoA and carbon dioxide molecules. The acetyl-CoA molecules enter the citric acid cycle occurring in the mitochondria and are used up in the production of ATP, CO2, and electrons carried by NADH and FADH2.

The electrons carried by NADH and FADH2 from glycolysis and citric acid cycle are used in the oxidative phosphorylation pathway occurring inside the mitochondrion for transformation of oxygen molecules into water molecules with release of ATP.

8 0

3 years ago

The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago

Why the answer is A?

Marizza181 [45]

Answer:

Becuase A makes sence

Explanation:

6 0

3 years ago

(b) Describe how a student could test cow's milk to show whether it contains protein

marin [14]

Milk contains a lot of proteins in them it contains calcium protein potassium iodine. Phosphorus. It also contains vitamins b1 and b12.

5 0

3 years ago

Which of the following is the best way to get all of the air out of a bottle?

GenaCL600 [577]

Answer:

d

Explanation:

because oil is not air

3 0

3 years ago