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3 years ago

Paula and Chad each ate 2/5 of a batch of cookies. Together, what fraction of the batch of cookies did they eat?

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

$\bf \stackrel{Paula}{\cfrac{2}{5}}+\stackrel{Chad}{\cfrac{2}{5}}\implies \cfrac{2+2}{5}\implies \cfrac{4}{5}$

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147.1 is what percent of 155

Harrizon [31]

Solution for what is 147.1% of 155

155/x=100/147.1
(155/x)*x=(100/147.1)*x - we multiply both sides of the equation by x
155=0.67980965329708*x - we divide both sides of the equation by (0.67980965329708) to get x
155/0.67980965329708=x
228.005=x
x=228.005

now we have:
147.1% of 155=228.005

3 0

3 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$

Now we have everything in order to replace into formula (1):

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

4 0

3 years ago

Henry places £6000 in an account which pays 4.6% compound interest each year

aivan3 [116]

Answer:

£ 6,564.70

Step-by-step explanation:

Henry places £6000 in an account which pays 4.6% compound interest each year. Calculate the amount in his amount after 2 years

Compound Interest formula =

A = P(1 + r/n)^nt

A = Final Amounrt

P = Principal = £6,000

r = Interest rate = 4.6%

t = Time in years = 2 years

n = Compounding frequency = Yearly = 1

First, convert R percent to r a decimal

r = R/100

r = 4.6%/100

r = 0.046 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 6,000.00(1 + 0.046/1)^(1×2)

A = £ 6,564.70

The amount in his account after 2 years = £ 6,564.70

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