X + y = 8
x - y = 12
--------------add
2x = 20
x = 20/2
x = 10
x + y = 8
10 + y = 8
y = 8 - 10
y = -2
ur numbers are 10 and -2
Answer:
Option D. A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left
Step-by-step explanation:
we have

Divide the compound inequality into two inequalities
-----> inequality A
Multiply by -1 both sides

Divide by 5 both sides

The solution of inequality A is the interval ----> (-∞,10]
All real numbers less than or equal to 10
-----> inequality B


Multiply by -1 both sides

Divide by 5 both sides

Rewrite

The solution of the inequality B is the interval ----> (4,∞)
All real numbers greater than 4
The solution of the compound inequality is
(-∞,10] ∩ (4,∞)= (4,10]
All real numbers greater than 4 and less than or equal to 10
A number line with an open circle on 4 with shading to the right and a closed circle on 10 with shading to the left
10/10 = 1
so the are 10 tenths in 1 whole
Answer:
-128
Step-by-step explanation:




Hope this helps!
Answer:
In interval form range is [-2,16]
Step-by-step explanation:
Here we can see that given equation is circle
whose center is (5,7 ) and radius is 8 ,
Range of the circle is actually values of y it changes from
if (h,k) is the center and r is the radius of circle then range is given by
k-r ≤y ≤ k+r
here in the question k = 7 and r =9
therefore range is
7-9 ≤y ≤ 7+9
-2 ≤y ≤ 16
In interval form [-2,16]