Explain how both are correct./ bc I have the answer but I didn’t explain

Mathematics

1 answer:

Rudik [331]3 years ago

5 0

They are both correct becuase lets say it was a shirt that was $30 and it was 30% off. For Jasani it would be 30 * 0.7 which equals $9 then you would subtract this 30 - 9 = 21. For Hanna it would be 30 - 0.3(30) which equals $21. So in the end they are both correct!

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The diameter of fishing line varies. Fishing lines can have a diameter as small as 2 x 102 inch and as large as 6 x 10-2 inch. H

Reil [10]

Answer:
3 times

Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in

We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3

This means that the large diameter is 3 times the small one.

Hope this helps :)

4 0

3 years ago

Find the x- and y- intercepts of parabola y=5x^2-16x+10

____ [38]

Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$