What is the solution to this equation?2х- 5+ 3x = 35

Mathematics

2 answers:

defon3 years ago

6 0

I want to honestly dieee

Elena L [17]3 years ago

4 0

Answer:

Step-by-step explanation:

3x +2x - 5 = 35 to rearrange makes it easier

then, add 3x and 2x which gives you 5x - 5 = 35

then using addition property of equality (APOE) add 5 to both sides which then cancels out the 5 on the left side of the equation and then add 5 to the right side which makes it 40. Then your equation looks like 5x = 40. then using division property of equality, divide by 5 on both sides and 40/5= 8!

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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$