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3 years ago

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Mathematics

2 answers:

konstantin123 [22]3 years ago

7 0

Answer: -3 degrees F

Step-by-step explanation:

It dropped by 9 so you do 6-9 which = -3

nirvana33 [79]3 years ago

6 0

Answer:

-3 degrees

Step-by-step explanation:

6-9=-3

you subtract by 9 because the temperature dropped by 9 degrees

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3. Solve 2log4y - log4 (5y - 12) = 1/2<br>

Ilia_Sergeevich [38]

Answer:

y = 4 or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2) remove logarithm

y^2/(5y-12) = 2 cross multiply

y^2 = 10y-24 rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

4 0

3 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago

HELPPPPPPP!!!!!!! Plz

Natalka [10]

The answer is to this question is a)strong positive...

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=50%20%2B%20%2840%20-%2015%29%20%5Cdiv%206" id="TexFormula1" title="50 + (40 - 15) \div 6" alt=

IgorLugansk [536]

Answer:

12.5

Step-by-step explanation:

first you do the one in the 40-15 then you add 50 the you divide by 6

8 0

3 years ago

Read 2 more answers

4. The balance in Tom's account was

MrRissso [65]

Answer:

His balance is $3778.28

4 0

3 years ago

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