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1 answer:
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According to the image:
the right hexagonal pyramid surface area is given by the following formula:
S = 3√3 / 2) a² + 3a √h²+3a²/4
a = the base edge
h = the height of the pyramid
looking at the image a =6m, h =21m - 7m= 14m
so the surface area is S = 3√3 / 2) 6² + 3*6√14²+3*6²/4 =93.53+ 14.93=108.46 m²
for the another one
the figure is a prism hexagonal
its surface area is
SA= 6ah +3√3 a²
a= base edge, h =height
in our case a =6m and h = 7m
so SA= 6*6*7 + 3√3 * 6²= 252 + 187 = 439 m²
finally, the surface area of the complete image is
ST= S + SA = 108.46 m² + 439 m² = 547.52 m²
it is so approximate
to <span>B. 615.53 m2
look at the image</span>
the right hexagonal pyramid surface area is given by the following formula:
S = 3√3 / 2) a² + 3a √h²+3a²/4
a = the base edge
h = the height of the pyramid
looking at the image a =6m, h =21m - 7m= 14m
so the surface area is S = 3√3 / 2) 6² + 3*6√14²+3*6²/4 =93.53+ 14.93=108.46 m²
for the another one
the figure is a prism hexagonal
its surface area is
SA= 6ah +3√3 a²
a= base edge, h =height
in our case a =6m and h = 7m
so SA= 6*6*7 + 3√3 * 6²= 252 + 187 = 439 m²
finally, the surface area of the complete image is
ST= S + SA = 108.46 m² + 439 m² = 547.52 m²
it is so approximate
to <span>B. 615.53 m2
look at the image</span>