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Ad libitum [116K]
3 years ago
9

A bundled computer package costs $760.50. There is an 8 percent convenience fee for assembling the package. How much will the co

mputer cost, with assembly?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0
So we need to find 8% of 760.50 then add it to the original cost of the computer package. 
To find 8%, multiply like what is below. 

$760.50 × .08 = 60.84
$60.84 is 8% of $760.50
Add both totals together to get the cost of the computer, with assembly

Answer: $821.34
You might be interested in
Find the coordinates of P so that P partitions AB in the ratio 3:4 with A(-9,-9) and B(5,-2).
ivolga24 [154]

The coordinates of point P are (-3 , -6)

Step-by-step explanation:

If point (x , y) partitions line AB where A = (x_{1},y_{1}) and B = (x_{2},y_{2})

at a ratio m_{1}:m_{2} from A then:

1. x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}

2. y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ P partitions AB in the ratio 3 : 4

∴ m_{1}:m_{2} = 3 : 4

∵ A = (-9 , -9) and B = (5 , -2)

- Substitute the coordinates of points A and B in the rules above

∵ x=\frac{(-9)(4)+(5)(3)}{3+4}

∴ x=\frac{-36+15}{7}

∴ x=\frac{-21}{7}

∴ x = -3

The x-coordinate of P is -3

∵ y=\frac{(-9)(4)+(-2)(3)}{3+4}

∴ y=\frac{-36+(-6)}{7}

∴ y=\frac{-42}{7}

∴ y = -6

The y-coordinate of P is -6

The coordinates of point P are (-3 , -6)

Learn more:

You can learn more about the mid-point of a segment in brainly.com/question/5223123

#LearnwithBrainly

5 0
4 years ago
Help ASAP
RoseWind [281]

Answer:

List from least to greatest:-16,-10,-3,5

List from closest to zero to the very far:-3,5,-10,16

Step-by-step explanation:

In order to know if the answer is accurate,draw a number line of directed numbers...the very far negative numbers,are said to be the least than the numbers almost close to zero...

7 0
4 years ago
Read 2 more answers
ou find a deck of cards and know that the deck has too many clubs and spades in it. The deck has 59 cards. If you were to draw t
sashaice [31]
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

\dfrac{\binom{13}1\binom{13+c}1}{\binom{59}2}=\dfrac{13(13+c)}{1711}

but this would imply that c=-4, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".

Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

\dfrac{\binom{13}1}{\binom{59}1}\cdot\dfrac{\binom{13+c}1}{\binom{58}1}=\dfrac{13(13+c)}{3422}

and solving gives c=5, which makes more sense. Then the number of extra spades in the deck must be 2.
7 0
3 years ago
Put in a new
mr_godi [17]

Answer:

$110

Step-by-step explanation:

The first step would be to multiply 11 and 5 to get the result of 55.

Then, you would multiply 55 by whatever the cost per square yard is, which in this case is $2.

Finally after multiplying 55 and 2 you would get the answer of $110.

Hope this helped! Have a great day! :)

3 0
3 years ago
How many times does 50 go into 102?​
saw5 [17]
2 because 50 x 2 is 102
3 0
4 years ago
Read 2 more answers
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