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gogolik [260]
3 years ago
7

How do I solve system of equations substitution method??!!?!???

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
For example:

x+2y=7
6x+7y=2
__________

x=7-2y *
6*(7-2y)+7y=2 **

__________

x=7-2y
42-12y+7y=2
__________

x=7-2y
-5y=-40
__________

x=7-2y
y=8

x=-9
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Please help thanks ❗​
mojhsa [17]

Answer:

The Two Column Proof is given below.

Step-by-step explanation:

Given:

\overline{MP} \cong \overline{MN}

\overline{PO} \cong \overline{NO}

To Prove:

∠ P ≅ ∠ N

Proof:

In  Δ MPO  and Δ MNO

STATEMENT                                              REASONS  

1. MP ≅ MN                                   1. Given

2. PO ≅ NO                                  2. Given

3. MO ≅ MO                                 3. Reflexive property

4. ΔMPO ≅ ΔMNO                       4. Side-Side-Side congruence test}

5. ∠MPO ≅∠MNO                        5. Corresponding parts of congruent Triangles

i.e ∠ P ≅ ∠ N                                 ..................Proved

3 0
3 years ago
If the car you bought in question 3 had a sales price of $45,000, how much interest did you end up paying in the end?
Roman55 [17]
This is a backup question it would be great to state what question 3 was please
3 0
3 years ago
Read 2 more answers
A square window has a perimeter of (8x+12) feet. Write an expression that represents the side length of the window (in feet). Pl
luda_lava [24]
Perimeter of a square = 4L
4L = (8x+12)ft
L= (2x+3)ft
5 0
3 years ago
Really Need Help ! ASAP
SCORPION-xisa [38]

Answer:

hope the above solution will help you

5 0
3 years ago
Evaluate the surface integral. s x ds, s is the part of the plane 18x + 9y + z = 18 that lies in the first octant.
IceJOKER [234]
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.

(x,0,0)\implies 18x+9\cdot0+0=18\implies x=1
(0,y,0)\implies 18\cdot0+9y+0=18\implies y=2
(0,0,z)\implies 18\cdot0+9\cdot0+z=18\implies z=18

Now that we know the vertices of the surface \mathcal S, we can parameterize it by

\mathbf s(u,v)=\langle(1-u)(1-v),2u(1-v),18v\rangle

where 0\le u\le1 and 0\le v\le1. The surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=2\sqrt{406}(1-v)\,\mathrm du\,\mathrm dv

With respect to our parameterization, we have x(u,v)=(1-u)(1-v), so the surface integral is

\displaystyle\iint_{\mathcal S}x\,\mathrm dS=2\sqrt{406}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-u)(1-v)^2\,\mathrm dv\,\mathrm du=\frac{\sqrt{406}}3
5 0
3 years ago
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