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gogolik [260]
3 years ago
7

How do I solve system of equations substitution method??!!?!???

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
For example:

x+2y=7
6x+7y=2
__________

x=7-2y *
6*(7-2y)+7y=2 **

__________

x=7-2y
42-12y+7y=2
__________

x=7-2y
-5y=-40
__________

x=7-2y
y=8

x=-9
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Find the volume of the sphere pictured below. The sphere has a radius of 20 cm. Use 3.14 for pi. Give your answer rounded to the
zhenek [66]

Answer:

33493.3

Step-by-step explanation:

Sphere

Solve for volume

V=4/3πr^3 4/3*3.14*20^3=33493.3

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Scale factor word problem<br> Someone please help me!
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1. Niles is making a map of his neighborhood. He uses a scale in which 1 cm = 5 km. The distance between his house and the school is 8.5 km.

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8.5 ÷ 5 = 1.7

There will be 1.7 centimeters between his house and school.

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2 years ago
Mr.Ramirez teaches dance. He has 16 sixth-grade students and 24 seventh-grade students. He wants to put the students in equal gr
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Mr. Ramirez can use many different group sizes, but the largest group size possible is 8.  This results in 16/8=2 sixth-grade groups and 24/8=3 seventh-grade groups.
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3 years ago
Brandon decided to make his own hand sanitize. To be effective and sanitizer
icang [17]

Answer:

Step-by-step explanation:

The water has to be 100% - 60% = 40%

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2 years ago
What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t
weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

L=BC\\W=AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

A(2,-1),B(5,2),C(12,-5),D(9,-8)

<em>Find out the distance BC</em>

we have

B(5,2),C(12,-5)

substitute in the formula

d=\sqrt{(-5-2)^{2}+(12-5)^{2}}

d=\sqrt{(-7)^{2}+(7)^{2}}

d_B_C=\sqrt{98}\ units

<em>Find out the distance AB</em>

we have

A(2,-1),B(5,2)

substitute in the formula

d=\sqrt{(2+1)^{2}+(5-2)^{2}}

d=\sqrt{(3)^{2}+(3)^{2}}

d_A_B=\sqrt{18}\ units

<em>Find out the area</em>

A=(L)(W)

we have

L=d_B_C=\sqrt{98}\ units

W=d_A_B=\sqrt{18}\ units

substitute

A=(\sqrt{98})(\sqrt{18})=42.0\ units^2

4 0
3 years ago
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