The radius of cone is 2 inches
<em><u>Solution:</u></em>
<em><u>The volume of cone is given by formula:</u></em>
Where,
"V" is the volume of cone
"r" and "h" are the radius and height of cone respectively
Given that, volume of a cone is 16 pi cubic inches
Its height is 12 inches
Therefore, we get,
V = cubic inches
h = 12 inches
r = ?
<em><u>Substituting the values in formula, we get</u></em>
Since, radius cannot be negative, ignore r = -2
Thus radius of cone is 2 inches
Answer
A = 46.3°
B = 75.7°
c = 3.5
Explanation
We will be using both Cosine and Sine rule to solve this.
For Cosine rule,
If a triangle ABC has angles A, B and C at the points of the named vertices of the tringles with the sides facing each of these angles tagged a, b and c respectively, the Cosine rule is given as
c² = a² + b² - 2ab Cos C
a = 3.0
b = 4.0
C = 58°
c² = 3² + 4² - 2(3)(4)(Cos 58°)
c² = 9 + 16 - (24)(0.5299)
c² = 25 - 12.72 = 12.28
c = √12.28 = 3.50
To find the other angles, we will now use Sine Rule
If a triangle ABC has angles A, B and C at the points of the named vertices of the tringles with the sides facing each of these angles tagged a, b and c respectively, the sine rule is given as
So, we can use the latter parts to solve this
B = ?
b = 4.0
C = 58°
c = 3.5
We can then solve for Angle A
The sum of angles in a triangle is 180°
A + B + C = 180°
A + 75.7° + 58° = 180°
A = 180° - 133.7° = 46.3°
Hope this Helps!!!