<span>We first calculate the annual straight-line depreciation for the starting 8-year useful lifespan. This is given by the value minus the salvage value (23,000 - 1,500) divided by the 8 year lifespan, resulting in annual depreciation of 2,687.50 dollars. After four years at this rate, the vehicle has depreciated in value by 2,687.50 * 4 dollars (10,750) and has a present value of 12,250 dollars. The useable life is then reduced by 2 years so we must recalculate the straight-line depreciation. This is given by present value minus salvage cost (12,250 - 1,500) divided by the remaining 2 years of usable life. This results in a depreciation expense in both years 5 and 6 of $5,375.</span>
Answer:
200
Step-by-step explanation:
For problems like this we can use algebra to help us, the farenheight 6 hours ago was:
(2xt)-6=-20
We have to balance the sides out, first we minus 6
2xt=-26
Now we can divide by 2
t=-13
We now know the temperature 6 hours ago was -13
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H =
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer