All categories

3 years ago

Pleaseeeee help me!!!

Mathematics

2 answers:

erik [133]3 years ago

4 0

Answer:

D m = -1

Step-by-step explanation:

To find the slope of the line

m = (y2-y1)/(x2-x1)

= (-12--11) / (10-9)

= (-12+11) / (10-9)

= -1/1

= -1

dusya [7]3 years ago

4 0

Answer:

Step-by-step explanation:

3/-5

4/-6

5/-7

6/-8

it is the only one that follows the correct pattern

You might be interested in

The makers of a soft drink want to identify the average age of its consumers. A sample of 25 consumers was taken. The average ag

Lelu [443]

Answer:

a.1.90 years

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this question:

$n = 25, \sigma = 3.8$

$M = 2.575*\frac{3.8}{\sqrt{25}} = 1.90$

So the correct answer is:

a.1.90 years

8 0

3 years ago

What is the area of the figure?

rewona [7]

Answer:

57 square feet

Step-by-step explanation:

Split the boxes into two parts.

One box measuring 11.5 ft long and 3 ft wide. (Box A)

The second box measuring 7.5 ft long and 3 ft wide. (Box B)

Area (figure) = Area of box A + Area of box B

Area of box A

3 × 11.5 = 34.5 ft²

Area of box B

3 × 7.5 = 22.5 ft²

Area of figure = 34.5 + 22.5

Area of figure = 57 ft²

3 0

3 years ago

832,651,097 help me<br> With problem #3

Alborosie

Answer:

Hi :D

Nearest hundred thousand: 832,650,000

Nearest thousand: 832,651,000

Nearest million: 833,000,000

Nearest hundred: 832,651,100

Hope this helps!

Sahkfam (:

6 0

3 years ago

1.27(v+-7)=-17.78<br> Solve for v.

Alexandra [31]

Answer:

V= −7

Step-by-step explanation:

In pic

( hope this helps have a great day :) .)

8 0

3 years ago

The density of people (number of people per mile) during the evening rush hour for the 5 mile stretch along a certain sidewalk i

Kisachek [45]

Answer:

a. $\int\limits^5_0 {f(x)} \, dx$

Step-by-step explanation:

Since f(x) is the function for the populational density at a certain sidewalk for a 5 mile stretch, a definite integral of that function will yield the total number of people within the integration intervals. If we are interested in the number of people in the whole 5 mile stretch, we must integrate f(x) from x = 0 miles to x = 5 miles:

$\int\limits^5_0 {f(x)} \, dx$

Therefore, the answer is alternative a.

5 0

3 years ago