A mixed number greater than 8.45? my answers are

2 answers:

8 0

We can easily see that only 8 216/360 is greater than 8 162/360. It means the correct answer is C: From the given mixed numbers, only 8 3/5 is greater than 8.45.

Vitek1552 [10]3 years ago

8 0

I think the answer is C. because 8.45 in mixed number form is 8 9/20

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PLEASE I NEED HELP

9966 [12]

The general equation of the circle is:

$(x-h)^{2} +(y-k)^{2} =r^{2}$

(h,k) is the center of the circle and r is the radius. We are given the coordinates of the center. So we can write the equation of the circle as:

$(x+4)^{2} +(y+3)^{2} =r^{2}$

In order to complete the equation, we need the radius of the circle. Using the given point we can find the radius. Using the point in the above equation, we get:

$(6+4)^{2}+(2+3)^{2}=r^{2} \\ \\ 
100+25=r^{2}$

Thus the value of r² is 125. Using the value in equation of the circle, we get:

$(x+4)^{2} +(y+3)^{2} =125$

The radius of the circle is √125.

8 0

3 years ago

Read 2 more answers

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have