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IrinaK [193]
3 years ago
6

Simplify to an expression of the form (a sin(θ)). 2sin(/8)2cos(/8)

Mathematics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

Your expression equals 2 \sin(\frac{\pi}{4}) assuming the problem was to simplify 2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8}) to the form a\sin(\theta).

Step-by-step explanation:

2\sin(\frac{\pi}{8}) 2\cos(\frac{\pi}{8})

2(2)\sin(\frac{\pi}{8})\cos(\frac{\pi}{8})

Let's use the following identity: 2\sin(A)\cos(A)=\sin(2A)

2\sin(2 \cdot \frac{\pi}{8})

2 \sin(\frac{\pi}{4}) which is comparable to the form a\sin(\theta).

a=2

\theta=\frac{\pi}{4}

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eimsori [14]

Answer:

8,920 ÷ 80=111.5

892 ÷ 8=111.5

89.2 ÷ 0.08=111.5

.892 ÷ 0.008=111.5

Step-by-step explanation:

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2 years ago
Write the slope-intercept form of the equation of the line through the given points through {-3,1} and (-5,5)
Zigmanuir [339]

Slope = -2/1

work is provided in the image attached.

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3 years ago
Flies in a nest double every 12 hours. If the nest starts with 10 flies, how many will you have in 3 days?
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You would have 640 flies in 3 days.
5 0
3 years ago
Anand needs to hire a plumber. He's considering a plumber that charges an initia
Ede4ka [16]

Complete question :

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?​

Answer:

65 + 28H < 250

Number of hours Anand can afford = 6 hours

Step-by-step explanation:

Given the following information :

Initial hourly rate = $65

Hourly rate = $28

Number of hours worked (whole number) = H

Maximum budgeted amount to spend = $250

Therefore ;

(Initial charge + total charge in hours) should not be more than $250

$65 + ($28*H) < $250

65 + 28H < 250

Number of hours Anand can afford :

65 + 28H < 250

28H < 250 - 65

28H < 185

H < (185 / 28)

H < 6.61

Sinve H is a whole number, the number of hours he can afford is 6 hours

5 0
4 years ago
In 1998 the population of a city was 100,000. Then each year for the next five years the population increases by 3%. Write and e
sertanlavr [38]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ population = 100,000 x 1.03^5

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

3 0
3 years ago
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