Answer:
Total eclipse was minutes longer than in 2005.
Step-by-step explanation:
It is given in the question that total eclipse in 2003 lasted minutes and in 2005 it lasted 3/8 of a minute.
We have to calculate how much longer did it last in 2003.
So we have to subtract the duration in 2003 by duration in 2005
Total time taken in 2003- total time taken in 2005
minutes
Answer:
I am pretty sure its 30 students
Answer:
1. A = 40 units²
2. A = 72 units²
3. B) 45
Step-by-step explanation:
1. This shape comprises 4 congruent triangles with base of 5 units and height of 5 units.
Area of a triangle = 1/2 x base x height
Therefore, area of polygon = 4(1/2 x 5 x 4)
= 40 units²
2. This shape comprises two pairs of congruent triangles.
Area of a triangle = 1/2 x base x height
Therefore, area of polygon = 2(1/2 x 2 x 6) + 2(1/2 x 10 x 6)
= 72 units²
3. Count the number of shaded squares:
9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45 units²
Answer: B
Step-by-step explanation:
The p-value is greater than the significance level (0.09 > 0.05), so we "fail to reject" H0.
The p-value and significance level are provided from the questions .
General rule of P value : When a P value is less than or equal to the significance level, you reject the null hypothesis.
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18
15/30: 5/10 OR 1/2
45/60: 8/12 OR 4/6
Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number.
5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8.
2/5 and 1/2: 2/5 and 2.5/5
9/9 and 5/7: 9/9 and ~5.7/9
Rewrite each in simple form: Find greatest common factor and divide.
9/54: 1/6
20/40: 1/2
100/110: 10/11
Are these fractions equivalent?
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole.
In what situation can you use multiplication to find equivalent fractions?
I'm sorry but I do not understand this question.
</span>Source(s):<span>I hope I helped, seeing as I have graduated with a math degree.</span>