* Channel proteins- these are proteins with a hydrophilic pore where specific ions are able to pass through the membrane. Each channel protein is specific to an ion. This is the only way ions can travel through the membrane. They are trans membrane proteins.
* Carrier proteins- these are proteins which allow larger or polar molecules through the membrane. They are trans membrane proteins.
Carrier proteins essentially “carry" signals that are not soluble in aqueous solution through the blood stream to their target cells. Carrier proteins for hydrophilic signals prevent degradation of the signal. Channel proteins are embedded in cell membranes. They often are receptors (though not always), and when activated, allow specific ions to pass through the membrane.
A channel protein is a special arrangement of amino acids which embeds in the cell membrane, providing a hydrophilic passageway for water and small, polar ions. Like all transport proteins, each channel protein has a size and shape which excludes all but the most specific molecules
The carrier protein facilitate diffusion of molecules across the cell membrane. The protein is imbedded in the cell membrane and covers the entire membrane. This is important because the carrier must transport the molecule in and out of the cell.
Answer:
<em>The correct answer is C) The organs mature</em>
Explanation:
During the 3rd trimester, the baby continues with its development. Structures like the bones have completely formed but are soft. The baby is capable of opening and closing its eyes. During the 3rd trimester, the organs of the baby are fully mature and can carry out their own functions. By the end of the third- trimester, the baby turns in head- down position. Hence, the correct option is C.
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
The answer is C. exocytosis.
Exocytosis is a process in which vesicles in the cell moves to the cell membrane to fuse with it. This way, the vesicles release their contents to the extracellular matrix. The purpose of exocytosis is to transport large molecules out of the cell because they are too large to pass passively through the cell membrane.
Exocytosis is the opposite process of<span> endocytosis,</span><span> in which cell engulfs molecules, such as proteins. Pinocytosis is fluid endocytosis. In exocytosis, cell transports molecules, such as proteins, out of the cell.</span>
Answer: Protons
Explanation: Protons and Nuetrons are found in the Nucleus of a atom