Two equivalent forms:
x1, y2
Explain: x1 creates the shape of the polynomial and y1 sharpens it, to make it look more realistic and more rounded.
Answer:
JK = 24
Step-by-step explanation:
Δ BKJ and Δ BCA are similar triangles and ratios of corresponding sides are equal, that is
= 
, substitute values
= 
( cross- multiply )
5JK = 120 ( divide both sides by 5 )
JK = 24
By solving given equations, the value of c is 30.
Given two equations
x + 2y = 10 and
3x + 6y = c
These lines represents the same line for some constant c.
Value of c:
x + 2y = 10-------------(1)
3x + 6y = c-------------(2)
Dividing equation (2) by 3
After solving the above equation, we get
x + 2y = c/3-----------(3)
Remember that a line is written as ax + by = c, in our case, both lines have a =1 and b = 2. Therefore, in orther that the two lines are equal, we need that, 10 = c/3
c = 10 × 3 = 30
c = 30
Therefore,
The value of c is 30.
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Answer:
x= 0
Step-by-step explanation:
Let's first simplify the equation to make the PEMDAS process easier.
8x-10=3x-10+7x
8x-10=10x-10
Now lets start the subtracting and dividing process.
8x=10x
0=2x
0=x
First translate the English phrase "Four times the sum of a number and 15 is at least 120" into a mathematical inequality.
"Four times..." means we're multiplying something by 4.
"... the sum of a number and 15..." means we're adding an unknown and 15 and then multiplying the result by 4.
"... is at least 120" means when we substitute the unknown for a value, in order for that value to be in the solution set, it can only be less than or equal to 120.
So, the resulting inequality is 4(x + 15) ≤ 120.
Simplify the inequality.
4(x + 15) ≤ 120
4x + 60 ≤ 120 <-- Using the distributive property
4x ≤ 60 <-- Subtract both sides by 60
x ≤ 15 <-- Divide both sides by 4
Now that we have the inequality in a simplified form, we can easily see that in order to be in the solution set, the variable x can be no bigger than 15.
In interval notation it would look something like this:
[15, ∞)
In set builder notation it would look something like this:
{x | x ∈ R, x ≤ 15}
It is read as "the set of all x, such that x is a member of the real numbers and x is less than or equal to 15".
