<span>Consider the triangles ERT and CTR.
|ER|=|CT| shown
(</span>Therefore, one can say that segment ER is congruent to segment CT.)
m(R)=m(T)= 90°shown
(By the definition of a rectangle, all four angles measure 90°)
|RT|=|TR|
so we have Side Angle Side congruence.
By the <span>(SAS) Theorem, the triangles are congruent.
Answer: </span><span>C (SAS) Theorem</span>
Answer:
The farmers in regions II, IV, and VI had exactly two of the three Summing the numbers in these regions 25 + 15 + 10 we find the that 50 farmers grew exactly two of the three.
X = 3
and
formula -
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
(x1,y1) = (4,1)
(x2,y2) =( 5,3)
(y-1)/(x-4) = (3-1)/(5-4)
y-1/x-4 = 2/1
y-1 = 2x - 8
y = 2x - 7
the solution will be x= 3 and y = -1
Answer:
Step-by-step Explanation:
Given:
∆UVW,
m < U = 33°
m < V = 113°
VW = u = 29 m
Required:
Area of ∆UVW
Solution:
Find side length UV using Law of Sines
U = 33°
u = VW = 29 m
W = 180 - (33+113) = 34°
w = UV = ?
Cross multiply
Divide both sides by sin(33) to make w the subject of formula
(rounded to nearest whole number)
Find the area of ∆UVW using the formula,
(to nearest tenth).
