Answer:
m∠SQR = 74°
Step-by-step explanation:
Points P, Q and R are collinear.
Therefore, angles PQR and angle RQS are the linear pair of angles.
Since linear pair of angles are supplementary angles.
m∠PQR + m∠RQS = 180°
By substituting the measures of the given angles,
(3m + 1) + (2m + 4) = 180
5m + 5 = 180
5m = 180 - 5
5m = 175
m = 
m = 35
Since, m∠SQR = (2m + 4)°
= (2×35) + 4
= 74°
Therefore, m∠SQR = 74° is the answer.
Answer:
The factors of given expression are 10+10√2 and 10-10√2.
Step-by-step explanation:
We have given a quadratic expression.
s²-20s-100
We have to find factors of given expression.
We use quadratic formula to find factors.
x = (-b±√b²-4ac) / 2a
From given expression, a = 1 , b = -20 and c = -100
Putting values in above formula, we have
x = (-(-20)±√(-20)²-4(1)(-100) ) / 2(1)
x = (20±√400+400 ) / 2
x = (20±√800) / 2
x = (20± √400×2) / 2
x = (20±20√2) / 2
x = 10±10√2
Hence, the factors of given expression are 10+10√2 and 10-10√2.
Answer:
Step-by-step explanation:
Sum of the interior angles of polygon = (n-2) * 180
= (4 - 2) *180 = 2 *180 = 360
n is no of sides of the polygon
I think it would be 70382
Answer:
A). A(t) = P(1+r/n)^(nt)
B). DA/Dt = np(1+r/n)^(t)
C). A(5) =$ 5664.0
D).t = approximately 13.5 years
Step-by-step explanation:
A(t) = P(1+r/n)^(nt)
P = $5000
n= t
r= 2.5%
After five years t = 5
A(t) = P(1+r/n)^(nt)
A(5) = 5000(1+0.025/5)^(5*5)
A(5) = 5000(1+0.005)^(25)
A(5)= 5000(1.005)^(25)
A(5) = 5000(1.132795575)
A(5) = 5663.977875
A(5) =$ 5664.0
When the balance A= $7000
A(t) = P(1+r/n)^(nt)
7000= 5000(1+0.025/n)^(nt)
But n= t
7000= 5000(1+0.025/t)^(t²)
7000/5000= (1+0.025/t)^(t²)
1.4= (1+0.025/t)^(t²)
Using trial and error
t = approximately 13.5 years
