N³- n² + 3n - 3 = (n²+3 )(x-1 )
Answer:
B
Step-by-step explanation:
We are given:
![y=4x](https://tex.z-dn.net/?f=y%3D4x)
![2x^2-y=0](https://tex.z-dn.net/?f=2x%5E2-y%3D0)
We are going to put 4x in place of the second y since the first y equaled it:
![2x^2-4x=0](https://tex.z-dn.net/?f=2x%5E2-4x%3D0)
So we can factored this equation:
![2x(x-2)=0](https://tex.z-dn.net/?f=2x%28x-2%29%3D0)
This implies 2x=0 or x-2=0.
2x=0
Divide both sides by 2:
x=0
x-2=0
Add 2 on both sides:
x=2
If x=0 and y=4x, then y=4(0)=0 so we have (0,0) is an intersection.
If x=2 and y=4x, then y=4(2)=8 so we have (2,8) is an intersection.
Answer:
It is D so u are right
Step-by-step explanation:
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