Simplify i^31 (click photo for options)

an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor line is 105ft long. how far from the tower c

Fynjy0 [20]

Answer:

Let x be how far from the tower can it be placed

by Pythagorus theorem

x^2 + 96^2 = 105^2

x=√(105^2 -96^2 )=√1809 = 42.532340 = 42.5 ft

3 0

3 years ago

There are three options for fans purchasing a band's new release CD. They can purchase the CD, a premium CD bundle, or a deluxe

cluponka [151]

Answer:

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

Step-by-step explanation:

Let c represents the number of CD's

Let d represents the number of deluxe bundles

Let p represents the number of premium bundles.

Now according to the given statement:

c = $15

d = c+2p =

d = 15+2p --------equation 1

455c+87p+35d = $12,845 --------equation 2

Now substitute the value of d in equation 2 to find the value of p

455c+87p+35d = $12,845

455(15)+87p+35(15+2p) = $12,845

6825+87p+525+70p=$12,845

Now combine the like terms:

6825+157p+525 = $12,845

Now shift all the like terms to the R.H.S

157p= 12845-6825-525

157p = 5495

Divide both sides by 157

157p/157 = 5495/157

p = 35

Now substitute the value p =35 in equation 1.

d = 15+ 2p

d = 15+2(35)

d = 15+70

d = 85

Therefore we have found that,

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

4 0

3 years ago

Your teacher asks you to find a recipe that includes two ingredients with a ratio of 1/2 cup/ 1/8 cup. a. give an example of two

Ksivusya [100]

A. Sugar And Brown Sugar (For Cookies)

B. No.

C 1/2 Cup (INGREDIENT) And 1/8 Cup (INGREDIENT)

7 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

2 years ago

Which system is represented by the graph?

WITCHER [35]

Answer:

pallar system is represent

3 0

3 years ago