Answer:
x+2
Step-by-step explanation:
![\frac{x ^{2} + 4x + 4 }{x + 2} \\ \frac{(x) ^{2} + 2 \times x \times 2 + (2) ^{2} }{x + 2} \\ \ \frac{(x + 2) ^{2} }{x + 2} \\ \frac{(x + 2)(x + 2)}{x + 2} \\ x + 2](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%5E%7B2%7D%20%2B%204x%20%2B%204%20%7D%7Bx%20%2B%202%7D%20%20%5C%5C%20%5Cfrac%7B%28x%29%20%5E%7B2%7D%20%2B%202%20%5Ctimes%20x%20%5Ctimes%202%20%2B%20%282%29%20%5E%7B2%7D%20%20%7D%7Bx%20%2B%202%7D%20%20%5C%5C%20%5C%20%20%20%5Cfrac%7B%28x%20%2B%202%29%20%5E%7B2%7D%20%7D%7Bx%20%2B%202%7D%20%20%5C%5C%20%20%5Cfrac%7B%28x%20%2B%202%29%28x%20%2B%202%29%7D%7Bx%20%2B%202%7D%20%20%5C%5C%20x%20%2B%202)
Answer:
<em>" Expected Payoff " = $ 6.70</em>
Step-by-step explanation:
Consider the steps below;
![Probability of Winning the 550 Dollar Prize - 1 / 200,\\Probability * Money Won = " Expected Payoff " For The 550 Dollar Prize,\\\\1 / 200 * 550,\\" Expected Payoff " - 2.75 Dollars,\\\\Probability of Winning the 510 Dollar Prize - 1 / 200,\\\\1 / 200 * 510,\\" Expected Payoff " - 2.55 Dollars,\\\\Probability of Winning the 280 Dollar Prize - 1 / 200,\\\\1 / 200 * 280,\\" Expected Payoff " - 1.4 Dollars,\\\\](https://tex.z-dn.net/?f=Probability%20of%20Winning%20the%20550%20Dollar%20Prize%20-%201%20%2F%20200%2C%5C%5CProbability%20%2A%20Money%20Won%20%3D%20%22%20Expected%20Payoff%20%22%20For%20The%20550%20Dollar%20Prize%2C%5C%5C%5C%5C1%20%2F%20200%20%2A%20550%2C%5C%5C%22%20Expected%20Payoff%20%22%20-%202.75%20Dollars%2C%5C%5C%5C%5CProbability%20of%20Winning%20the%20510%20Dollar%20Prize%20-%201%20%2F%20200%2C%5C%5C%5C%5C1%20%2F%20200%20%2A%20510%2C%5C%5C%22%20Expected%20Payoff%20%22%20-%202.55%20Dollars%2C%5C%5C%5C%5CProbability%20of%20Winning%20the%20280%20Dollar%20Prize%20-%201%20%2F%20200%2C%5C%5C%5C%5C1%20%2F%20200%20%2A%20280%2C%5C%5C%22%20Expected%20Payoff%20%22%20-%201.4%20Dollars%2C%5C%5C%5C%5C)
![Conclusion ; Expected Payoff = 6.70 Dollars](https://tex.z-dn.net/?f=Conclusion%20%3B%20Expected%20Payoff%20%3D%206.70%20Dollars)
95% C.I. = mean + or - 1.96(standard deviation / sqrt(sample size))
95% C.I. = 57 + or - 1.96(3.5/sqrt(40) = 57 + or - 1.085 = 57 - 1.085 to 57 + 1.085 = 55.92 to 58.09
Therefore, 95% of the mean will occur in the interval 55.92 to 58.09
Answer:
0.83
Step-by-step explanation:
The radius is <span>24.5
R = C/2pi
</span>