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Dominik [7]
3 years ago
15

The three lines 8x+3y=12, 6y-7x=24, x+9y+33=0 intersect to form a triangle. Find the coordinates of its centroid

Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

coordinates of its centroid=(-1,-1)

Step-by-step explanation:

The given three lines are:

8x+3y=12,                                     (1)

6y-7x=24                                      (2)

and x+9y+33.                               (3)

Multiplying equation (1) by 2 and subtract the equation (2), we get

23x=0⇒x=0,

Putting the value of x=0 in equation (2), we get

6y=24

y=4

Now, multiply the first equation by 3 and subtract the equation (3), we get

23x=69⇒x=3

Putting the value of x=3 in equation (1), we get

24+3y=12

3y=-12

y=-4

Also, multiplying the equation (3) by 7 and add the equation (2), we get

69y=-207

y=-3

Putting the value of y=-3 in equation (2), we get

6(-3)-7x=24

-18-24=7x

x=-6

So the centroid is located at (the average of the three vertices):  

x=\frac{0+3-6}{3}=\frac{-3}{3}=-1 and y=\frac{4-4-3}{3}=\frac{-3}{3}=-1.

Thus, the coordinates of its centroid=(-1,-1)


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20+23+12=43+12=55

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The midpoint of AB is M(-3, 0). If the coordinates of A are (1,-4), what are the coordinates of B?
zimovet [89]

Using the given information, the coordinates of B are (-7, 4)

<h3>Midpoint of a Line </h3>

From the question, we are to determine the coordinates of B.

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

From the given information,

The midpoint of AB is M(-3, 0)

and

The coordinates of A are (1,-4)

Let the coordinates of B be (x₁, y₁)

Then,

-3 = (1 + x₁)/2

-6 = 1 + x₁

x₁ = -6 -1

x₁ = -7

Also,

0 = (-4 + y₁)/2

0 = -4 + y₁

y₁ = 0 + 4

y₁ = 4

Hence, the coordinates of B are (-7, 4)

Learn more on Midpoint of a line here: brainly.com/question/18315903

#SPJ1

7 0
2 years ago
IQ scores on the WAIS test approximate a normal curve with a mean of 100 and a standard deviation of 15. What IQ score is identi
riadik2000 [5.3K]

Answer:

IQ scores of at least 130.81 are identified with the upper 2%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 100 and a standard deviation of 15.

This means that \mu = 100, \sigma = 15

What IQ score is identified with the upper 2%?

IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.

Z = \frac{X - \mu}{\sigma}

2.054 = \frac{X - 100}{15}

X - 100 = 15*2.054

X = 130.81

IQ scores of at least 130.81 are identified with the upper 2%.

7 0
3 years ago
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