All categories

2 years ago

A triangle has side lengths of 7.1, 12.6, and b. Which of the following CANNOT be b? (A) 5.7 (B) 7.5 (C) 10.1 (D) 18.5 (E) 19.9

1 answer:

8 0

-- When the 7.1 and 12.6 sides both point in exactly the same direction,
their open ends are 5.5 apart. So the missing side must be greater than 5.5 .
All of the choices are greater than 5.5 , so we haven't found it yet.

-- When the 7.1 and 12.6 point in opposite directions, their open ends are
19.7 apart. So the missing side can't be greater than 19.7, otherwise the
two sides we know couldn't reach between its ends. <u>Choice 'E'</u> is greater
than 19.9, so it can't be the missing side.

You might be interested in

Solving system of equations by substitution

weeeeeb [17]

Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation

3x+2y=16
3x+2(3x-10)=16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4

sub back

y=3x-10
y=3(4)-10
y=12-10
y=2

x=4
y=2
(4,2) is soluiton

5 0

3 years ago

Solve for x- <br> 6x^2 + 36x + 54 = 0

lions [1.4K]

Answer:

-3

Step-by-step explanation:

$6x^2+36x+54=0$

First, you can factor out a 6:

$6(x^2+6x+9)=0$

Next, you can factor the quadratic:

$6(x+3)^2=0$

Since the only value of x that could set this equation equal to 0 is -3, that is the answer. Hope this helps!

5 0

3 years ago

The graph of y = 2 is shifted down by 6 units and to the left by 9 units.

luda_lava [24]

Answer:

(-9, -4)

Step-by-step explanation:

7 0

2 years ago

2. List the like terms in each of the following<br> i) 4x2 , -5x , 6 , 7x , -2x2 , -3

Vikentia [17]

he is the best way to get a free agent and I ask 6262626

8 0

2 years ago

Read 2 more answers

A padlock has the digits 0 through 9 arranged in a circle on its face. A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is fou

stepan [7]

Answer:

The total numbers of possible combinations are 3430.

Step-by-step explanation:

Consider the provided information.

A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.

Here, for the first digit we have 10 choices.

For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.

For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.

For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.

So the number of choices are:

$10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430$

Hence, the total numbers of possible combinations are 3430.

8 0

2 years ago