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3 years ago

30. The box-and-whisker plot shows the average temperatures in Tucson, Arizona in December. (1 point)

Mathematics

1 answer:

IrinaK [193]3 years ago

8 0

Answer:

About half of the days in December has average tempetare between 52 and 60 degrees

(SEE THE ATTACHMENT)

Step-by-step explanation:

See the box-and-whisker plot.

Median = 58

1st quartile (which is the median of all value below 58) = 52

2nd quartile (which is the median of all value above 58) = 60

From 1st quartile to median = Almost quarter of the values

From median to 2nd quartile = Almost quarter of the values

From 1st quatile to 2nd quartile = Almost half of the values

1st statement is wrong

2nd statement is correct

3rd statement is wrong (Coldest day was 49 degrees)

4rth statement is wrong (Hottest day was 68 degrees)

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5TH GRADE LEVEL QUESTION: LOOK AT PHTO AND ANSWER HANDING OUT BRAINLIEST.

mafiozo [28]

Answer:

The volume of Jill's rectangular prism is 40 cm^3

Step-by-step explanation:

w*l*h=area

2*2*10

4*10

40 cm^3

Hope this helps!!

5 0

3 years ago

For the functions f(x) and g(x), determine the domain of (f ∙ g)(x) (the product of f and g).

Luba_88 [7]

Answer: Domain: (-∞, 0) U (0, ∞)

Step-by-step explanation:

$\frac{12}{x} *-8x^{3}$

$=-96x^2$

Domain: (-∞, 0) U (0, ∞)

7 0

2 years ago

The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)

bekas [8.4K]

Answer: F(x) = 2*sin(x/10 +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10 +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10 +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10 +(3/2)*pi) + 5

8 0

3 years ago

Values greater then 1653

krek1111 [17]

Answer:

1654,1655,1656,1657,1658,1659,1660

Step-by-step explanation:

They all come after the value of 1653

7 0

3 years ago

Simplify the expression to a polynomial in standard form:

lukranit [14]

Answer:

$-x^3+7x^2-6x-18$

Step-by-step explanation:

Use distributive property: $(-x+3)(x^2-4x-6)$

What is -x * x^2? Answer: -x^3

What is 3 * x^2? Answer: +3x^2

What is -x * -4x? Answer: +4x^2

What is 3* -4x? Answer: -12x

What is -x * -6? Answer: +6x

What is 3 * -6? Answer: -18

$-x^3+3x^2+4x^2-12x+6x-18$

Combine like terms, and your answer would be....

$-x^3+7x^2-6x-18$

Hope this helps :)

Have a great day!

7 0

2 years ago