X = 6
24 divided by 4 equals 6
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Y = mx + b
First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0
Set them equal to each other,
m(4) + b - 1 = m(5) + b - 7
If you bring the b over to the left hand side it becomes
m(4) + b - b - 1 = m(5) - 7
m(4) - 1 = m(5) - 7
Solve for m
6 = m
Plug m = 6 into either equation from the beginning,
m(4) + b - 1 = 0
6(4) + b - 1 = 0
24 + b - 1 = 0
b = -23
Knowing m and b we can now make an equation
y = mx + b
y = 6x -23 Final answer
Answer:
b i believe
Step-by-step explanation: