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enot [183]
3 years ago
12

Ax + bx - 15 = 0;x How do you solve this?

Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

Step-by-step explanation:

ax+bx-15=0\\=> (a+b)x-15=0\\=>(a+b)x=15\\=>x=\frac{15}{(a+b)}

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Please answer it soon
Jet001 [13]
Hey dude we’re both from Nepal so here’s the written worksheet hope it helps :)

6 0
2 years ago
A rectangular block of copper metal has a mass of 1800 grams. The dimensions of the block
Hoochie [10]
Use formula p=m/v
P is density
M is mass
V volume
So you have the volume already now 8x5x4= 160 which is the volume
P= 1800/160 after you divide you get 11.25
The density is 11.25
3 0
3 years ago
PLEASE PLEASE PLEASE HELP!!
Marta_Voda [28]
Okay I'll try to show it step by step

Step 1. So first you need to recognise that the diagram is a right angled triangle, with the right angle being at the bottom. This means we can do Pythagoras' Theorem.

Step 2. Now that you know you can use Pythagoras' Theorem, you can apply it. If you don't know, the theorem is a² + b² = c², with, in this case, a being 5 and b being 8. This means we can do 5² + 8² = 25 + 64 = 89.

Step 3. From the previous step, we now know that the length of the side including x is √89, and because we know that part of this side is 3, if we subtract 3 from √89 we get the value of x, so: √89 - 3 = 9.434 - 3 = 6.434, which is your answer.

I hope this helps!
5 0
3 years ago
Which graph below shows the solutions for the linear inequality ys x-3?
liraira [26]

Answer:

Graph A.

Step-by-step explanation:

Given the inequality: y\leq \dfrac{1}{4}x-3

Since the sign is "less than or equal to", the line cannot be dotted. Therefore, Options C and D are incorrect.

Since the sign is a "less than" sign, the required region must be below the line. Therefore, the graph which shows the given inequality is Graph A.

4 0
3 years ago
The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). At which points could the vertex of the right angle in t
Pie

Answer:

(–1, 1)  and (4, –2)

Step-by-step explanation:

we know that

The vertex of the right angle of the triangle could be situated at a point with the same x-coordinate of point A and the same y-coordinate of point B or at a point with the same x-coordinate of point B and the same y-coordinate of point A

we have

A(4, 1) and B(–1, –2)

so

a point with the same x-coordinate of point A and the same y-coordinate of point B is the point (4,-2)

a point with the same x-coordinate of point B and the same y-coordinate of point A is  (-1,1)

therefore

(–1, 1)  and (4, –2)

3 0
3 years ago
Read 2 more answers
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