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3 years ago

Divide. simplify your answer (2x^4-6x^3+4x^2-3x)*(2x) pls show work

Mathematics

2 answers:

denis23 [38]3 years ago

8 0

Distribute

2x × 2x^4 + 2x × -6x^3 + 2x ×4x^2 + 2x × - 3x

Take out the constants

(2 × 2)xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × 2 to 4

4xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Use Product Rule: x^a x^b = x^a + b

4x^1 + 4 + 2x × -6x^3 + 2x ×4x^2 + 2x × -3x

Simplify 1 + 4 to 5

4x^5 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Take out the constants

4x^5 + (2 × -6)xx^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × -6 to -12

4x^5 - 12xx^3 + 2x × 4x^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^1 + 3 + 2x × 4x^2 + 2x -3x

Simplify 1 + 3 to 4

4x^4 - 12x^4 + 2x ×4x^2 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + (2 × 4)xx^2 + 2x × -3x

Simplify 2 × 4 to 8

4x^5 - 12x^4 + 8xx^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^4 + 8x^ 1 + 2 + 2x × -3x

Simplify 1 + 2 to 3

4x^5 - 12x^4 + 8x^3 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + 8x^3 + (2 × -3)xx

Simplify 2 × -3 to -6

4x^5 - 12x^4 + 8x^3 - 6xx

Use the Product Rule: x^a x^b = x^a + b

Lilit [14]3 years ago

3 0

Answer:

4x^5 - 12x^4 + 8x^3 - 6x^2

Step-by-step explanation:

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Alex787 [66]

To solve this problem, we must assume that the man undergoes constant acceleration as he goes down the river (therefore no other forces must act on him except gravity). Therefore we can use the formula below to calculate for the duration of his fall:

y = y0 + v0 t + 0.5 a t^2

where y is the distance and y0 = 0 since we set the reference point at the bridge, v0 is the initial velocity and is also equal to v0 = 0 since the man started from rest, therefore the equation becomes:

y = 0 + 0 t + 0.5 a t^2

y = 0.5 a t^2

Rewriting in terms of t:

t^2 = 2 y / a

t = sqrt (2y / a)

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3 years ago

Indicate if the answer is positive or negative 332÷(-2)

liraira [26]

Answer:

Negative

Step-by-step explanation:

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4 years ago

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Is this relation a function? Justify your answer.

faltersainse [42]

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2 years ago

HELP PLEASE I NEED HELP

Vesna [10]

$C. \: 8 \sqrt{3}$ ✅

Step-by-step explanation:

$\sqrt{192} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times {2}^{2} \times 3} \\ = \sqrt{ {8}^{2} \times 3 } \\ = 8\sqrt{3}$