What are the zeros of the function f(x)=3x^2-3x-6
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These numbers are "a" and "b".
Sum is 64, so a+b=64
Difference is 42 so a-b=42
So you've got:
When a+b=64 and a=53 you've got:
53+b=64
b=11
So these numbers is 53 and 11.
Sum is 64, so a+b=64
Difference is 42 so a-b=42
So you've got:
When a+b=64 and a=53 you've got:
53+b=64
b=11
So these numbers is 53 and 11.