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3 years ago

8

How many solutions does -5x+10x+3=5x+6

1 answer:

lana66690 [7]3 years ago

7 0

Answer:x=.3

Step-by-step explanation:

-5x+10x+3=5x+6

10x+3=6

10x=3

x=.3

one solution

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HIGH POINTS)Please help! (20 points)

USPshnik [31]

Answer:

What the other person said

Step-by-step explanation:

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3 years ago

Could someone help me with this?

hodyreva [135]

Step-by-step explanation:

Identity the variable:

Initial Velocity is 35.

Initial Height is 204

Final Height is 0.

What looking for the time.

So we have

$0 = - 16 {t}^{2} + (35)t + 204$

Use Quadratic Formula,

$- b± \frac{ \sqrt{b {}^{2} - 4ac} }{2a}$

A is -16, B is 35 , C is 204.

So we have

$- 35± \frac{ \sqrt{ {35}^{2} - 4( - 16)(204) } }{ - 32}$

$- 35± \frac{ \sqrt{1225 + 2240} }{ - 32}$

$- 35± \frac{ \sqrt{3465} }{ - 32}$

${35} ± \frac{ \sqrt{3465} }{ - 32}$

The positve solution is

$4.83$

So the answer is 4.83 seconds

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2 years ago

Sam said the square root of a rational number must be a rational number. Jenna disagreed. She said that it is possible that the

Nat2105 [25]

Jenna is correct. This is because the square root of 2 is an irrational number. And if the number is a prime number, the answer is less likely to have a rational square root.

6 0

3 years ago

Read 2 more answers

PLEASE ILL MAKE BRAINIEST!!!

expeople1 [14]

Answer:

The area of rectangle BEFD is 180 square units.

Step-by-step explanation:

After checking the figure given, we have the following information:

$AD = 15$ , $AB = 12$ , $BC = 15$ , $CD = 12$

By Pythagorean Theorem, we determine the length of the line segment BD:

$BD = \sqrt{AB^{2}+AD^{2}}$ (1)

$BD = \sqrt{12^{2}+15^{2}}$

$BD = 3\sqrt{41}$

In addition, we know the following characteristics of the rectangle BEFD:

$BD = EF$ , $EF = EC + CF$ , $BE = FD$ (2), (3), (4)

By Pythagorean Theorem:

$BC^{2} = BE^{2}+EC^{2}$ (5)

$CD^{2} = CF^{2}+DF^{2}$ (6)

By (3), (4), (5) and (6):

$BC^{2} = BE^{2} + EC^{2}$ (7)

$CD^{2} = (EF-EC)^{2} + BE^{2}$ (8)

By (7) in (8):

$CD^{2} = (EF-EC)^{2}+ (BC^{2}-EC^{2})$

$CD^{2} = EF^{2}-2\cdot EF\cdot EC + EC^{2}+BC^{2}-EC^{2}$

$CD^{2} = EF^{2}-2\cdot EF\cdot EC +BC^{2}$

Then, we clear $EC$ :

$2\cdot EF\cdot EC = EF^{2} + BC^{2} - CD^{2}$

$EC = \frac{EF^{2}+BC^{2}-CD^{2}}{2\cdot EF}$

If we know that $EF = 3\sqrt{41}$ , $BC = 15$ and $CD = 12$ , then the length of the segment $EC$ is:

$EC = \frac{75\sqrt{41}}{41}$

And the length of the line segment $CF$ is:

$CF = EF - EC$

$CF = 3\sqrt{41}-\frac{75\sqrt{41}}{41}$

$CF = \frac{48\sqrt{41}}{41}$

And the length of the line segment $DF$ is determined by Pythagorean Theorem:

$FD = \sqrt{CD^{2}-CF^{2}}$

$FD = \sqrt{12^{2}-\left(\frac{48\sqrt{41}}{41} \right)^{2}}$

$FD = \frac{60\sqrt{41}}{41}$

And the area of the rectangle is determined by the following formula:

$A = FD\cdot EF$

$A = \left(\frac{60\sqrt{41}}{41} \right)\cdot (3\sqrt{41})$

$A = 180$

The area of rectangle BEFD is 180 square units.

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3 years ago

If the sides of the triangle 14,15 and 19 is it a triangle acute right or obtuse

jasenka [17]

I believe that is acute

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3 years ago