Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).
<h3>How many bowls of cereal would kathy have?</h3>
We know that for each bowl, she needs 1/2 cups of milk.
And we also know that she has a total of (3 + 3/5) cups of milk.
To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:
(3 + 3/5)/(1/2)
We can rewrite the total as:
3 + 3/5 = 15/5 + 3/5 = 18/5
Then the quotient becomes:
(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5
So she can make 7 bowls of cereal (and some leftover milk).
If you want to learn more about quotients:
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Answer:
Step-by-step explanation:
The formula for finding the midpoint of two coordinates is expressed as;
M(X,Y) = 
Given the coordinates c(-4,5) and d(-1,-4), x1 = -4, y1 = 5, x2 = -1 and y2 = -4.
For the X coordinate of the midpoint
X = x1+x2/2
X = -4+(-1)/2
X = -4-1/2
X = -5/2
X = -2.5
Similarly for Y:
Y = y1+y2/2
Y = 5+(-4)/2
Y = 5-4/2
Y = 1/2
Y = 0.5
Hence the midpoint coordinate of C(-4,5) and D (-1,-4) is (-2.5, 0.5)
Answer:
No because 21 is close to it.
Step-by-step explanation:
To be considered an outlier, it would need to be a farther distance such as the distance from 28 to 21.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
There is an association because the value 0.15 is not similar to the value 0.55
For the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.
The conditions that satisfy whether there exists an association between conditional relative frequencies are:
1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.
2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.
For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
We can conclude that there is an association because the value 0.15 is not similar to the value 0.55
