There are many polynomials that fit the bill,
f(x)=a(x-r1)(x-r2)(x-r3)(x-r4) where a is any real number not equal to zero.
A simple one is when a=1.
where r1,r2,r3,r4 are the roots of the 4th degree polynomial.
Also note that for a polynomial with *real* coefficients, complex roots *always* come in conjugages, i.e. in the form a±bi [±=+/-]
So a polynomial would be:
f(x)=(x-(-4-5i))(x-(-4+5i))(x--2)(x--2)
or, simplifying
f(x)=(x+4+5i)(x+4-5i)(x+2)^2
=x^4+12x^3+77x^2+196x+164 [if you decide to expand]
<h2>3</h2>
Step-by-step explanation:
The equation of line passing through the two points is 
When substituted,the equation becomes 
which when simplified is 
The line clearly passes through origin.
The distance between two points is 
Distance between origin and 
is 
.
Distance between origin and 
is 
Scale factor is 
So,scale factor is 
which when simplified becomes 3.
441ft² (i believe this is the answer, idk though, i might be wrong sorry)
Switch where the x and y are, then solve for y. f(x) = y.
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
Answer:
circle
Step-by-step explanation:
circle is a set of all those points in a plane that lie the same distance from a single point in the plane .
