The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D
Answer:
As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.
(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.
(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.
(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.
(iv) At point A, the driver will feel the lightest.
(v)The car can go that much fast without losing contact with the road at A can be determined as follow:
Fn=0 - lose contact with road
Fg= mv²/r
mg=mv²/r
v=sqrt (gr)
Answer:
20 m/s
Explanation:
The frictional force the road exerts on the car provides the centripetal force that keeps the car in circular motion along the curve:
where
F is the centripetal force
m is the mass of the car
r is the radius of the curve
v is the speed of the car
In this problem we have:
m = 2000 kg
r = 200 m
F = 4000 N is the maximum force
Re-arranging the equation, we can calculate the maximum speed v corresponding to this force:
B. convex lens forms larger virtual image, is the correct answer.
It is because we can't observe chemical properties from our naked eye. So, for observing these, we need to perform appropriate experiments that may need some specific conditions. So, they are harder to observe.
Hope this helps!
