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Kruka [31]
3 years ago
12

Which celestial objects come in direct contact with earth

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Sun

Explanation:

Any asteroid in space is a celestial body. Classification of Celestial Bodies. A star is a form of a celestial object made up of a shining spheroid of plasma held together by its own gravity. The nearby star to Earth is the Sun.

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A 40-kg worker climbs a ladder upwards for 15m. What work was done during their climb upwards?
Bingel [31]

Answer:

Explanation:

The work increased the potential energy

W = PE = mgh = 40(9.8)(15) = 5880 J(oules)

4 0
2 years ago
A clarinet behaves like a tube closed at one end. If its length is 1.0 m, and the velocity of sound is 344 m/s, what is its fund
miv72 [106K]

Answer:

Fundamental frequency = 1376Hz

3 0
4 years ago
Part D
Brrunno [24]

Answer:

i. The magnetic force of repulsion.

ii. The magnetic force of attraction.

Explanation:

A magnet is a material that has the attraction and repulsion capability. Magnets has two poles, north and south, thus would attract or repel another magnet in its neighborhood. It can either be a permanent or temporal magnet, and attracts ferrous metals.

i. In the case of two combinations where two ends are the same, it could be observed that the two ends (poles) repels each other. Thus since like poles repels, magnetic force of repulsion is felt.

ii. In the case of one combination in which the two ends are different, the two ends (poles) attract. Since unlike poles attracts, magnetic force of attraction is observed.

5 0
4 years ago
A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charg
BaLLatris [955]

Answer:

a.F=1.03\times 10^{-7}N

b.Repulsive

Explanation:

We are given that

q_1=7.45nC=7.45\times 10^{-9}C

1nC=10^{-9}C

q_2=4.22nC=4.22\times 10^{-9}C

r=1.66m

We know that

Electrostatic force =F=k\frac{q_1q_2}{r^2}

r=Distance between q_1\;and\;q_2

k=Constant=9\times 10^9Nm^2C^{-2}

Using the formula

a.The magnitude of the electrostatic force=F=\frac{9\times 10^9\times 7.45\times 10^{-9}\times 4.22\times 10^{-9}}{(1.66)^2}

The magnitude of the electrostatic force=F=1.03\times 10^{-7}N

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.

7 0
3 years ago
Trong mặt phẳng Oxy, chất điểm chuyển động với phương trình<br><br> Tìm quĩ đạo của chất điểm.
QveST [7]

Xin lỗi nhưng tôi cần ảnh để trả lời đúng câu hỏi của bạn, thưa ông.

Nếu bạn đăng lại với hình ảnh, tôi sẽ sẵn lòng giúp đỡ!

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