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Kruka [31]
3 years ago
12

Which celestial objects come in direct contact with earth

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Sun

Explanation:

Any asteroid in space is a celestial body. Classification of Celestial Bodies. A star is a form of a celestial object made up of a shining spheroid of plasma held together by its own gravity. The nearby star to Earth is the Sun.

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What is the density of an object with a volume of 20 cm3 and a mass of 40g?
melisa1 [442]
Density = mass/volume
Density = 40g/20cm^3
Density = 2g/cm^3
3 0
3 years ago
Correct your friend that says, "The dragster rounded the curve at a constant velocity of 100 km/h." In other words, what is wron
Ainat [17]

Answer:

Correct statement will be dragster rounded the curve with constant speed

Explanation:

It is given that his fried says that The dragster rounded the curve with a constant velocity of 100 km/hour

It is a wrong statement because in circular motion velocity will never constant as the direction of speed is always changing

The correct statement will be dragster rounded the curve with a constant speed because speed may be constant in circular motion

8 0
3 years ago
You are given two infinite, parallel wires, each carrying current.The wires are separated by a distance, and the current in the
miv72 [106K]

Answer:

A. Attractive

B. ( μ₀I² ) / ( 2πd )

Explanation:

A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.

B. Suppose that two wires of length l_1 and l_2 both carry the current I in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -

B_1 = μ₀I / 2πd

The force experienced by wire 2 should thus be -

F_2 = I( l_2 * B_1 )

= I * l_2 * B_1 * Sin( 90 )

= I * l_2 ( μ₀I / 2πd )

Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...

( F_2 / l_2 ) = ( μ₀I² ) / ( 2πd ) ... which is our solution

3 0
3 years ago
Please help! Will give brainliest. 10 points. Show work!
Natasha_Volkova [10]

Answer:

421.83 m.

Explanation:

The following data were obtained from the question:

Height (h) = 396.9 m

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

First, we shall determine the time taken for the ball to get to the ground.

This can be calculated by doing the following:

t = √(2h/g)

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 396.9 m

Time (t) =.?

t = √(2h/g)

t = √(2 x 396.9 / 9.8)

t = √81

t = 9 secs.

Therefore, it took 9 secs fir the ball to get to the ground.

Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:

Time (t) = 9 secs.

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

s = ut

s = 46.87 x 9

s = 421.83 m

Therefore, the horizontal distance travelled by the ball is 421.83 m

5 0
3 years ago
Anyone know the answer to this? Please help.. NO LINKS
Harlamova29_29 [7]
Option C homie. 0.00001 C at 2 meters is 0.225 N

4 0
3 years ago
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