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Kruka [31]
3 years ago
12

Which celestial objects come in direct contact with earth

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Sun

Explanation:

Any asteroid in space is a celestial body. Classification of Celestial Bodies. A star is a form of a celestial object made up of a shining spheroid of plasma held together by its own gravity. The nearby star to Earth is the Sun.

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Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted out
blondinia [14]

Answer:

\theta = 20.98 degree

Explanation:

As we know that the speed of the sound is given as

v = 332 + 0.6 t

now at t = 273 k = 0 degree

v = 332 m/s

so we have

a sin\theta = N\lambda

a sin\theta = N(\frac{v_1}{f})

now when temperature is changed to 313 K we have

t = 313 - 273 = 40 degree

now we have

v = 332 + (0.6)(40)

v_2 = 356 m/s

a sin\theta' = N(\frac{v_2}{f})

now from two equations we have

\frac{sin19.5}{sin\theta} = \frac{332}{356}

so we have

sin\theta = 0.358

\theta = 20.98 degree

7 0
3 years ago
What other factor affected the gravitational force between the two objects in this simulation?
neonofarm [45]

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases

7 0
3 years ago
What would be a good reason to increase friction between surfaces? to allow objects to slide past each other easily to reduce we
Lelu [443]
So basically the objects would be sandpaper and smooth metal, the sandpaper can indirectly touch the metal since it’s so smooth and it won’t cause any temp change either
5 0
2 years ago
Read 2 more answers
Kinetic energy problemset
Sonja [21]

Answer:

KE = 4 mv2 m = 2xKE valami. V m.

Explanation:

8 0
3 years ago
Pls help
belka [17]

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these  value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

4 0
2 years ago
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