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Kruka [31]
3 years ago
12

Which celestial objects come in direct contact with earth

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

Sun

Explanation:

Any asteroid in space is a celestial body. Classification of Celestial Bodies. A star is a form of a celestial object made up of a shining spheroid of plasma held together by its own gravity. The nearby star to Earth is the Sun.

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A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

3 0
2 years ago
1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground
Svetradugi [14.3K]
You have three known variables:

Acceleration - 9.8m/s^2
Time - 1.85s
Initial Velocity - 0m/s

For the first part of your question:

v = u + at

v = (0)+(9.8)(1.1)

v = 10.78 m/s  v=11 m/s (2 significant figures)

For the second part of your question:

v=u+at

v=(0)+(9.8)(1.85)
v=18.13 m/s



This still needs to be converted to m/h:

18.13m/s = 18.13\times 3600 metres/h=65628  metres/hour

65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h

= 41 mi/hr (2 significant figures)





5 0
3 years ago
Read 2 more answers
What human practices are destroying the rain forest?
marissa [1.9K]
Deforestation, the chopping off of the trees that can take thousands or even millions of years to grow again<span />
6 0
2 years ago
The earth____ around the sun because the earth___ we have night and day
Harrizon [31]

Answer:

The Earth Revolves around the sun because the Earth Tilts<u>,</u> we have night and day.

Explanation:

Hope this helps! <3

4 0
3 years ago
Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
makkiz [27]

The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

V^{2} = U^{2} - 2as

0 = (4)^{2} - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \frac{16}{0.402}

  = 39.801

a = 39.80 m/s^{2}

Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

7 0
2 years ago
Read 2 more answers
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