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3 years ago

14

What goes in to 37 and 100?

2 answers:

aleksandr82 [10.1K]3 years ago

7 0

Can you retype this question in another form? like are you asking for the prime numbers?

il63 [147K]3 years ago

5 0

Answer:

yes I agree, I don't know what you're asking

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What is the value of n

AnnZ [28]

It's N=9 it's really confusing but trust me it N

8 0

2 years ago

Read 2 more answers

(2x-7)-(4x^2+6x-3)+(x^2+4)

masha68 [24]

Answer:

$-3x^2-4x$

Step-by-step explanation:

Simplify:

$\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)$

$=2x-7-\left(4x^2+6x-3\right)+x^2+4$

Group same factor:

$=-\left(4x^2+6x-3\right)+x^2+2x-7+4$

Add :

$=-\left(4x^2+6x-3\right)+x^2+2x-3$

Apply the distributive law: -(a+b) = -a - b

$-\left(4x^2+6x-3\right)=-4x^2-6x+3$

$=-4x^2-6x+3+x^2+2x-3$

Group same factor:

$=-4x^2+x^2-6x+2x+3-3$

Subtract:

$=-4x^2+x^2-6x+2x$

Add:

$=-3x^2-6x+2x$

Group same factor:

$=-3x^2-4x$

Hence answer = $-3x^2-4x$

<u><em>~lenvy~</em></u>

8 0

1 year ago

Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

5 0

3 years ago

1 1/18 + 3 1/18 + 1 2/9 + 1 2/9

Misha Larkins [42]

Answer:

6.55555555556

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The are of a shaded region is 118 ft squared. Which equation can be- used to find the value of X, in feet?

Triss [41]

Answer:

$x^2+ 18x -130=0$

Step-by-step explanation:

Given

See attachment for diagram

Required

The equation to find x

First, calculate the area of the big rectangle using:

$Area = Length * Width$

So:

$A_1 = (x + 6) * (3x - 2)$

The smaller rectangle

$A_2 = (x - 1) * (2x)$

The difference between this areas give the area of the shaded region.

So:

$A_1 - A_1 = 118$

$(x+6)*(3x-2) - (x-1)*2x = 118$

Open brackets

$3x^2 - 2x + 18x -12 -2x^2 +2x = 118$

Collect like terms

$3x^2 -2x^2- 2x +2x+ 18x -12 - 118=0$

$x^2+ 18x -130=0$

<em>The above equation can be used to solve for x</em>

4 0

2 years ago