Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Your answer would be 4x-7=-3(3+4x) because it only has one solution which is x= -1/8
Answer:
Step-by-step explanation:
48% of n = 0.48n = 40.32
n = 84
20% of n = 0.20*84 = 16.8
Answer:
Step-by-step explanation:
markup is 3.50(0.60) = $2.10
sales price is 3.50 + 2.10 = $5.60
one could also just multiply the wholesale price by 1.60
3.50(1.60) = $ 5.60
32.00=3 tens 2 ones 30+2=32
