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larisa [96]
4 years ago
9

Simplify:

%29%7D" id="TexFormula1" title="\frac{1}{(x+3)(x+4)} +\frac{2}{(x+4)(x+5)}" alt="\frac{1}{(x+3)(x+4)} +\frac{2}{(x+4)(x+5)}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Harlamova29_29 [7]4 years ago
8 0

Answer:

\frac{3x+11}{(x+3)(x+4)(x+5)}

Step-by-step explanation:

Before adding we require the fractions to have a common denominator.

Multiplying the numerator/ denominator of the first fraction by (x + 5)

Multiplying the numerator/ denominator of the second fraction by (x + 3)

= \frac{x+5}{(x+3)(x+4)(x+5)} + \frac{2(x+3)}{(x+3)(x+4)(x+5)}

Now add the numerators leaving the common denominator

= \frac{x+5+2x+6}{(x+3)(x+4)(x+5)}

= \frac{3x+11}{(x+3)(x+4)(x+5)}

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