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natulia [17]
3 years ago
7

A ream of paper weighs 5 pounds and has dimensions of 8.5 inches by 11 inches by 2 inches.

Mathematics
1 answer:
devlian [24]3 years ago
6 0
S = 2 (lw + lh + hw)
S = 2 ((8.5)(11) + (8.5)(2) + (11)(2))
S = 2 (93.5 + 17 + 22)
S = 2 (132.5)
S = 265 sq in
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Somebody please help me on this?! What is the correct postulate or theorem for this one..
IRINA_888 [86]

Answer:

Segment Addition Postulate

Step-by-step explanation:

In geometry, the Segment Addition Postulate states that given 2 points A and C(in this case S and O), a third point B(in this case R) lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Meaning for R to lie on the line SO;

SR + RO must be equal to SO

7 0
3 years ago
Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass
Ratling [72]

The solution would be like this for this specific problem:

Volume of a cylinder = pi * r^2 * h 

Volume of a cone = 1/3 * pi * r^2 * h 

Total Height = 47

Height of the cone = 12

Height of the cylinder = 35

If the top half is filled with sand, then:

volume (sand) = pi * 4^2 * 36

volume (cone) =  1/3 * pi * 4^2 * 12

Total volume = 1960.353816 cubic millimeters

353816 / (10 * pi) = 62.4 seconds.

It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.

8 0
3 years ago
create a linear function f(x), whose graph has the given slope that meets the given condition. slope of -7, f(-5)=2
sergejj [24]
Our goal is to fit the given information into the slope-intercept form.
y=mx+b

We can place the slope in 'm.'
y= -7x+b

Then, input the values for the x and y.
2= -7(-5)+b
2=35+b
b=2-35
b= -33

'b' is the intercept, so now that we know that, we can plug in all the values and find our final equation.

y= -7x -33

8 0
3 years ago
Please help I don’t understand
julia-pushkina [17]
The answer is 32.14
3 0
3 years ago
The dimensions of the tank are 50 cm by 32 cm by 20 cm. The tank is full of water and sand. The ratio of the volume of water to
Sauron [17]

Given:

Dimensions of a tank are 50 cm by 32 cm by 20 cm

The tank is full of water and sand

Ratio of volume of water to the volume of sand is 5:1

To find:

Volume of water in the tank in liters

Solution:

Without loss of generality, let,

Length of tank = 50 cm

Breadth of tank = 32 cm

Height of tank = 20 cm

Then, we have,

Total Volume of the tank = Length * Breadth * Height

\Rightarrow Total Volume = 50*32*20 cc

\Rightarrow Total Volume = 32000 cc

It is given that,

Volume of water : Volume of sand = 5:1

\Rightarrow (Volume of water)/(Volume of sand) = 5/1

Cross multiplying, we have,

Volume of sand = (Volume of water)/5

It is also given that the tank is full of water and sand. This implies that,

Volume of water + Volume of sand = Total Volume

Using the value, we obtained, we get,

Volume of water + (Volume of water)/5 = Total Volume

\Rightarrow (6 * Volume of water)/5 = Total Volume

Plugging in the value of total volume, we get,

\Rightarrow (6 * Volume of water)/5 = 32000 cc

\Rightarrow Volume of water = \frac{32000*5}{6} cc

\Rightarrow Volume of water \approx 26,666.6667 cc

We know that,

1 cc = 0.001 liters

\Rightarrow 26,666.6667 cc = (26666.6667 * 0.001) liters

\Rightarrow 26,666.6667 cc \approx 26.667 liters

Thus, Volume of water in the tank is approximately 26.667 liters

Final Answer:

Volume of water in the tank (in liters) is approximately 26.667 liters

4 0
3 years ago
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