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AveGali [126]
4 years ago
8

Find sin3A, cos 3A and tan 3A when sin=1/2​

Mathematics
1 answer:
Slav-nsk [51]4 years ago
4 0

Answer:

Sin 3A = 1

cos 3A = 0

tan 3 A = undefined

Step-by-step explanation:

\sin A =  \frac{1}{2}  \\  \therefore \: \sin A =   \sin \: 30 \degree.. \bigg( \because \: \sin \: 30 \degree =  \frac{1}{2} \bigg) \\ \therefore \: A =   30 \degree \\  \\ now \\   \sin 3A =\sin (3 \times 30 \degree)= \sin \: 90 \degree = 1 \\  \\  \cos 3A =\cos (3 \times 30 \degree)= \cos \: 90 \degree = 0\\\\ \tan 3A =\tan (3 \times 30 \degree)= \tan \: 90 \degree =  \infty

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