The sum of two numbers is 50 and the difference is 12. What are the numbers?

Mathematics

2 answers:

Debora [2.8K]3 years ago

6 0

Answer: x=31 and y = 19

Step-by-step explanation:

X+y=50

X-y=12

2x + 0y = 62

Divide both sides by 2

2x/2 = 62/2

x = 31

Now find y by plugging in 31 for x

31+y = 50

Subtract 31

y = 50-31

y = 19

Strike441 [17]3 years ago

3 0

Answer:

The two numbers are 31 and 19

Step-by-step explanation:

Let x and y be the numbers

x+y = 50

x-y = 12

Add the two equations together

x+y = 50

x-y = 12

-----------------

2x +0y = 62

Divide by 2

2x/2 = 62/2

x = 31

Now find y

31+y = 50

Subtract 31

y = 50-31

y = 19

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Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
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\\\\\\
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\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
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since the distance AB cannot be a negative value, thus is not -3-√(130).