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sweet [91]
3 years ago
8

The sum of two numbers is 50 and the difference is 12. What are the numbers?

Mathematics
2 answers:
Debora [2.8K]3 years ago
6 0

Answer: x=31 and y = 19

Step-by-step explanation:

X+y=50

X-y=12

2x + 0y = 62

Divide both sides by 2

2x/2 = 62/2

x = 31

Now find y by plugging in 31 for x

31+y = 50

Subtract 31

y = 50-31

y = 19

Strike441 [17]3 years ago
3 0

Answer:

The two numbers are 31 and 19

Step-by-step explanation:

Let x and y be the numbers

x+y = 50

x-y = 12

Add the two equations together

x+y = 50

x-y = 12

-----------------

2x +0y = 62

Divide by 2

2x/2 = 62/2

x = 31

Now find y

31+y = 50

Subtract 31

y = 50-31

y = 19

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Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

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<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

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Answer:

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Step-by-step explanation:

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