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OLEGan [10]
3 years ago
6

Round $4.39 to the nearest dollar

Mathematics
1 answer:
pshichka [43]3 years ago
8 0
It would be 4 dollars
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What’s 17 * 17 * 17 , What’s 4 * 4 * 4 * 4 * 4 ?
vichka [17]

Answer:

17*17*17= 4913

4 * 4 * 4 * 4 * 4 = 1024.

Hope this helps.

3 0
3 years ago
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If f(x)=3x-2 and g(x)=2x+1,find (f-g)(x) <br><br> A. x - 3<br> B. 5x - 3<br> C. 3 - x<br> D. 5x - 1
Nady [450]

Answer:

A

Step-by-step explanation:

(f - g)(x)

= f(x) - g(x)

= 3x - 2 - (2x + 1)

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3 years ago
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Suppose you want to build a small walkway around your garden so that there is someplace to walk around and work on your vegetabl
wolverine [178]

Answer:

Approximately 3.5 feet - Option B

Step-by-step explanation:

Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.

( 30 + 2x ) * ( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) * ( 20 + 2x )"

600 + 100x + 4x^2 = 1000 - Subtract 1000 on either side, making on side = 0

4x^2 + 100x - 400 = 0 - Take the "quadratic equation formula"  

( Quadratic Equation is as follows ) - x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a},

x=\frac{-100+\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad \frac{5\left(\sqrt{41}-5\right)}{2},

x=\frac{-100-\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad -\frac{5\left(5+\sqrt{41}\right)}{2}

There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) \frac{5\left(\sqrt{41}-5\right)}{2}. The approximated value however is 3.5081...or approximately 3.5 feet.

4 0
3 years ago
If Carri has 2345 marbles and subtracts 2156 how much does she have left?
Ann [662]
2345
2156
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0189

189 marbles left
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