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sashaice [31]
3 years ago
14

7.3 × 9.6= Multiply decimals

Mathematics
1 answer:
cluponka [151]3 years ago
4 0
The answer to your question is 70.08
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What time is 5 1/4 hours after 7:00?
Wittaler [7]
Seven add five is 12 . A clock has four quarters , the first quarter is fifteen minutes.
Therefore, 5 1/5 hours after 7:00 = 12:15
4 0
2 years ago
Read 2 more answers
I need help please! ​
Sophie [7]

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

4 0
2 years ago
In a major hurry to finish this I was stuck doin other homework last year please help me finish this
Irina-Kira [14]

2 = m ≤ −9

3 = p ≥ 5

4  =  x < -10

5 = b < -10

6 = n < 5

7 = n < 6

8 = r ≤ 4

9 = x ≥ 9

10 = p ≤ 0

11 = x < 1

12 = a > 24

6 0
3 years ago
PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :) ​
Hoochie [10]

Answer:

$40.52

Step-by-step explanation:

You add the amount of all the t-shirts that Mike bought and subtract it from 100.

6 0
2 years ago
In the beginning of the study, a randomly selected group of 121 students scored an average of 252 words per minute on the readin
Alborosie

Answer:

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample size larger than 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

So

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

5 0
3 years ago
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