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Kisachek [45]
3 years ago
13

Write an equation for the nth term of the geometric sequence below: (Equation NEEDS to be written as gn=7(5)^(n-1) or as gn=2/3(

1/4)^(n-1) NOTICE NO SPACES & using ^ to represent an exponent)
Mathematics
1 answer:
andriy [413]3 years ago
8 0

Answer:

You didn't give the geometric sequence in question.

But to find the nth term of a geometric sequence, use the formula

Sn = ar^(n - 1)

Where a is the first term of the sequence

r is the common ratio of the sequence.

Example: To find the nth term of the geometric sequence

1/2, 1/4, 1/8, 1/16, ...

Here, a = 1/2

r = 1/4 ÷ 1/2 = 1/8 ÷ 1/4 = 1/16 ÷ 1/8 = 1/2.

Sn = (1/2)(1/2)^( n - 1)

Apply this method to the sequence you were given, it will be helpful.

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slamgirl [31]
The answer is d I think
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What is the total surface area of the rectangular<br> prism represented by this net?
dedylja [7]

Answer:

Total surface area of the rectangular  prism is 150.88 cm^2

Step-by-step explanation:

area of base = area of top

area of base = 5 x 3.1 = 15.5 cm^2

Area of small lateral surface having dimensions 3.1 cm x 7.4 cm is

=3.1 x 7.4 = 22.94 cm^2

Area of big lateral surface having dimensions 5 cm x 7.4 cm is

=5 x 7.4 = 37 cm^2

Total area of prism = 2 x 15.5 + 2 x 22.94 + 2 x 37 = 150.88 cm^2

total surface area of the rectangular  prism is 150.88 cm^2

7 0
3 years ago
Read 2 more answers
rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

5 0
3 years ago
If the vertex of f(x) is (0,3), what is the vertex for 3×f(x-2)? Explain please.
katen-ka-za [31]
Vertex of 3f(x-2) is (0-2,3\cdot3)=(-2,9)
8 0
4 years ago
Read 2 more answers
Which equation represents the line that passes through (-8.11) and<br>(4,7/2)?​
Len [333]

Answer:

y=-5/8x+6

Step-by-step explanation:

m=\frac{7/2 - 11}{4--8}

m=\frac{-15/2}{12}

m=-5/8

y=-5/8x+b

(-8,11)

11=-5/8 \times -8+b

b=11-(-5/8)(-8)

b=6

6 0
3 years ago
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