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Fittoniya [83]
4 years ago
15

Explain why an individual with a compromised immune system may not be able to fight infection

Mathematics
1 answer:
sveta [45]4 years ago
6 0
<span>TayTheGOAT  Beginner</span>Need the points is all the reason im here
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If f(x) = 2x2 + 3x and g(x) = x – 2, what is (f + g)(2)?
Trava [24]

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3 years ago
(-247.43)(-5) = (-1)(247.43)-1)(5)
steposvetlana [31]
1237.15=1237.15

There will be no negative number
6 0
3 years ago
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Explain how to use a pattern to find the product of a power of 10 and a decimal
Arte-miy333 [17]

for a power of ten all you need is just add a zero, example, 10 to the power of 10 just add ten zeros behind the 10 -------> 100,000,000,000

8 0
3 years ago
Hannah has a grid of squares that has 12 rows with 15 squares in each row. She colors 5 rows of 8 squares in the middle of the g
ASHA 777 [7]

Answer:Number of squares colored red= 180-40= 140 squares

Step-by-step explanation:

Hannah has a grid of squares that has 12 rows with 15 squares in each row. This means the length of the gris is 15 squares and the breadth is 12 squares.

Area of grid = length × breadth

=15×12 = 180

She colors 5 rows of 8 squares in the middle of the grid blue. This means the part coloured blue has a length of 8 squares and breadth of 5 squares.

Area of blue colored part = 8×5 = 40

Number of squares colored red= total number of squares - number of square colored blue= 180-40= 140 squares

8 0
3 years ago
n a major league baseball game, the average is 1.0 broken bat per game. (a) Find the probability of no broken bats in a game. (R
jeyben [28]

Answer:

a) Probability of no broken bats in a game P(X=0) = 0.3678

b) Probability of at-least broken bats in a game P(X≥2) = 0.2644

Step-by-step explanation:

we will use Poisson distribution

P(X=x) = e^(-λ) λ^ r/r!

a) Probability of no broken bats in a game P(X=0) = e^-1

                                                                                   = 0.3678

b) Probability of at-least two broken bats in a game

                                                                     P(X≥2) = 1-([p(x=0)+P(x=1)]

                                                                               = 1- (e^(-1)+e^(-1))

                                                                                  = 1-(0.3678+0.3678)

                                                                   P(X≥2)= 1- 0.7356

                                                                  P(X≥2)= 0.2644

                   

7 0
3 years ago
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