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Umnica [9.8K]
2 years ago
8

Which inequality is shown in the graph

Mathematics
1 answer:
pentagon [3]2 years ago
3 0

Answer:

Less than.

Step-by-step explanation:

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1. Mr. Miller is building a dollhouse
Lina20 [59]

Answer:

1 ft : 2.5 yd or 1 ft : 2 1/2 yd

Step-by-step explanation:

He wants a real dimension of 10 yards to be represented by a scale dimension of 4 ft.

4 ft : 10 yd

Divide both sides by 4.

1 ft : 2.5 yd or 1 ft : 2 1/2 yd

8 0
3 years ago
A hotel claims that 8585​% of its customers are very satisfied with its service. complete parts a through d below based on a ran
jek_recluse [69]
We can solve this problem using the binomial distribution. A binomial distribution<span> can be thought of as a success or failure outcome in an experiment or survey that is repeated multiple times. 
</span>Probability function of binomial distribution has the following form:
P= \frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}
p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6. 
We can now calculate the answer:
P= \frac{6!}{5!(6-5)!} 0.85^5(1-0.85)^{6-5}=0.39
The probability is 39%.
.
7 0
3 years ago
Easy but i'm confused yikes. (picture attached)
kirill115 [55]

Answer:

The second answer

Step-by-step explanation:

P'Q'R' is simply rotating PQR 90 degrees, it does not change the angle that it makes

8 0
3 years ago
Read 2 more answers
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
Chet found a pair of sunglasses that he would like to buy. they normaly cost $43.00, but this week they are on sale for only 7/8
Tresset [83]
Ok, so this is a simple problem 
since its 7/8 of the price now, you do $43 divided by 8 to get the unit rate...
5.375 which rounds up to $5.38.
now since theres only 7/8, do 5.38x7 and your answer will be $37.66
3 0
3 years ago
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