I need some help with a Math question. I'm not sure how to work it out. All help appreciated.
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Considering the definition of perpendicular line, the equation of of perpendicular line is y= -x +
.
A linear equation o line can be expressed in the form y = mx + b.
where
x and y are coordinates of a point.
m is the slope.
b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.
<h3>Perpendicular line</h3>Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.
<h3>Equation of perpendicular line in this case</h3>In this case, the line is 2x-y=8. Expressed in the form y = mx + b, you get:
-y=8 - 2x
y= (-2x +8)÷ (-1)
y= 2x -8
If you multiply the slopes of two perpendicular lines, you get –1. In this case, the line has a slope of 2. So:
2× slope perpendicular line= -1
slope perpendicular line= (-1)÷ (2)
<u><em>slope perpendicular line= -</em></u>
So, the perpendicular line has a form of: y= -x + b
The line passes through the point (9, 2). Replacing in the expression for perpendicular line:
2= (-)× 9 + b
2= - + b
2+ = b
<u><em /></u><u><em>= b</em></u>
Finally, the equation of of perpendicular line is y= -x +
.
Learn more about perpendicular line:
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