He has to sell in a month $26616.67.
Given that a local salesman receives a base salary of $975 monthly and he also receives a commission of 6% on all sales over $1200.
A numerical assertion wherein two articulations are delivered equivalent to each other is known as an algebraic condition.
Let the Sales amount be s.
We have:
Sales over 1,200 is written as
s-1200
6% is also 0.06 as a decimal,
so according to question, we have
0.06(s - 1200) + 975=2500
Now, we will apply the distributive property a(b+c)=ab+ac, we get
0.06s-0.06×1200+975=2500
Further, we want to simplify the left-hand side, we get
0.06s-72+975=2500
0.06s+903=2500
Furthermore, we will subtract 903 from both sides, we get
0.06s+903-903=2500-903
0.06s=1597
Now, we will divide both sides with 0.06, we get
0.06s/0.06=1597/0.06
s=26616.67
Hence, he have to sell in a month if he needed to have a monthly income of $2500 is $26616.67.
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