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makvit [3.9K]
3 years ago
6

Write an expression with a variable m, a coefficient -3, and a constant of 17

Mathematics
2 answers:
Svetlanka [38]3 years ago
6 0

Answer

-3m + 17

Step-by-step explanation:

A coefficient is a number that goes in front of the variable, so -3 would go in front of m. A constant is just a number on it's own, so it would be +17

spayn [35]3 years ago
4 0

Answer:

-3m-17 or -3m+17

Step-by-step explanation:

the variable is m

coefficient is the # before the variable: For example the 4 in 4x

The constant is like the added or subtracted #

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The RANGE of the function f is
monitta

Answer:

Step-by-step explanation:

The range of the function is what values of y from lowest to highest that are covered by the function.  The domain are the values on the left: A-E; the range are the values on the right: 1-3.  We state both domain and range in interval notation, stating only the lowest and highest values in either a set of brackets if the values are included, a set of parenthesis if the values are not included, or a mixture of both.  Our range is inclusive, so we mention the lowest and the highest only: [1, 3].

7 0
2 years ago
How much 3 1/4+9 3/8
antoniya [11.8K]

Answer:12 5/8

Step-by-step explanation:

Add the whole numbers together. 3 + 9 = 12

Multiply 1/4 so that it will have the same dnominator as 3/8. 2(1/4)= 2/8

Add the fractions together. 2/8 + 3/8 = 5/8.

Add the whole number and fraction to get a mixed number. 12 + 5/8 = 12 5/8

5 0
3 years ago
Let f(x)=(x^2)(e^5x)<br><br> find the derivative f'(x) and the second derivative, f"(x)
Wittaler [7]
F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² = 
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² ) 
7 0
3 years ago
Read 2 more answers
Need this help me will give brainllest to the one gives me all three answer
PilotLPTM [1.2K]

Answer:

the sum is -4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.<br><br> 16x0 + 2x2 • y –1
swat32

Given that,

The given expression is : 16x^0+2x^2{\cdot}y^{-1}

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

16x^0+2x^2{\cdot}y^{-1}

Put x = 2 and y = 4 in the above expression.

16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18

So, the value of the above expression is 18.

6 0
2 years ago
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